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attashe74 [19]
2 years ago
15

Henry correctly subtracted 3p+5/3p from p+3/p-2 and got 12p^2+9p-3p^2+p+10/(p-2)(3p). What is the simplified difference?

Mathematics
1 answer:
IrinaK [193]2 years ago
8 0

Answer:

Step-by-step explanation:

Henry subtracted ( 3p+5)/3p from ( (\frac{p+3}{p-2}) and got

\frac{(12p^{2}+9p-3p^{2}+p+10}{(p-2)(3p)}

We have simplify the difference

= \frac{(12p^{2}+9p-3p^{2}+p+10}{(p-2)(3p)} = \frac{(12p^{2}-3p^{2})+(9p+p)+10}{(p-2)(3p)}

= \frac{9p^{2}+10p+10}{(p-2)(3p)}

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