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andrezito [222]
2 years ago
12

The proof diagram to complete the question state the missing reason in the proof for the letter given

Mathematics
2 answers:
Zina [86]2 years ago
5 0
The required statements and proofs is given as follows:

     Statement                               Proof

     ∠1 ≈ ∠5                                  Given
     ∠4 ≈ ∠1                                  Vertical opposite angles
     ∠4 ≈ ∠5                                  Transitive property
        p ║ r                                    Parallel lines intersected by the transverse line q.
melisa1 [442]2 years ago
4 0

ANSWER

First proved that line p is parallel to line r

to proof

As given in the question

∠1 ≈∠5

∠1 and ∠5 are corresponding angles

by using the property of the corresponding angles

 two lines are cut by a transversal so that the corresponding angles are


congruent, then these lines are parallel.


As shown in diagram q is transversal line.

Thus by using the above property

line p is parallel to line r.

proof of 1(a)

REASON

Vertically opposite angle

The pair of angles formed when two lines intersect each other are called vertically opposite angles.

Thus

∠4 and ∠1 are vertically opposite angle

thus

∠4 ≈∠ 1

proof of 2(b)

REASON

Alternate interior angle

the pairs of angles on either side of the transversal and inside the two lines are called the alternate interior angles . If two parallel lines are cut by a transversal, then the alternate interior angles formed are congruent .

as line p is parallel to line r (proof above)

q is transversal

thus

∠4 ≈∠ 5

Hence proved

proof of 3 (c)

As ∠4 ≈∠5 (proof above)  

REASON

If two lines are cut by a transversal so that the alternate interior angles

are congruent, then these lines are parallel.

Thus by above property

line p is parallel to line r

Hence proved







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WINSTONCH [101]

Answer:

The standard form is 7x^7 +6x^5-3x^3 + 8x

Step-by-step explanation:

Given:

6x^5 + 8x-3x^3+7x^7

To Find :

standard form of 6x^5 + 8x-3x^3+7x^7

Solution:

A polynomial is in standard form when its term of highest degree is first, its term of 2nd highest is 2nd etc.

In order to write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write.

Now lets check the degree of each term in the polynomial

The degree of 6x is 5

The degree of 8x is 1

The degree of 3x is 3

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Now rewrite  the polynomial in the order of the degree, from highest to lowest

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4 0
2 years ago
The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,
dmitriy555 [2]

Answer:

0.025

Step-by-step explanation:

-This is a conditional probability problem.

-Let L denote lens defect and C charging defect.

#We first calculate the probability of a camera having a lens defect;

P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025

#Calculate the probability of a camera having a charging defect:

P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125

The  the probability that a camera has a lens defect given that it has a charging defect is calculated as:

P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025

Hence,  the probability that a camera has a lens defect given that it has a charging defect is 0.025

6 0
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Gill wears a device that counts the number of steps she takes every day. One day she did onefifteenth of her steps before breakf
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Answer:

6000 steps

Step-by-step explanation:

1/15 +1/10+1/2=2/30+3/30+15/30=20/30=2/3

2/3=12000 steps

1/3=6000 steps

3/3=18000 steps

Her total steps should be 18000 and she has done 12000 steps.

18000-12000=6000 steps

6 0
2 years ago
the graph of g(x) is a translation of the function f(x) = x2. the vertex of g(x) is located 5 units above and 7 units to the rig
bulgar [2K]
Translation of 7 units to the right ⇒ subtract 7 units to the argument ⇒ f(x-7)

Translation of 5 units up ⇒ add 5 units to the function ⇒ f(x) + 5

g(x) = f (x-7) + 5 = (x-7)^2 + 5

The subtraction of 7 units to the argument of the function (this is x) translates the function 7 units to the right.

Adding 5 units to the function f, translates the graph 5 units up.
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