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GuDViN [60]
2 years ago
8

It takes one machine 25 minutes to pick a bale of cotton and another machine 30 minutes to compete the same job. If both machine

s are used, how long will it take them to pick a bale of cotton?
Mathematics
1 answer:
gladu [14]2 years ago
6 0
The first machine works at the rate x = 1 bale/ 25 min.
The second machine works at the rate y = 1 bale/30 min.

The combined rate is
x + y = 1/25 + 1/30 bales/min
         = (30 + 25)/(25*30) = 55/750
         = 11/150 bales/min

The time for both machines to pick 1 bale of cotton is
(1 bale)/(11/150 bales/min) = 150/11 min = 13.64 min

Answer: 13.6 minutes
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A loaded moving truck is traveling 30 mph faster than a freight train. in the time it takes the train to travel 135 miles, the truck travels 225 miles. find the speed of the truck.

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(x-30)=speed of train
the time it takes the train to travel 135 miles, the truck travels 225 miles...
135/(x-30)=225/x
the you multiply on both sides the x values and get...
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2 years ago
Patricia can drive 36 kilometers for every 3 liters of gas she puts in her car
Anna35 [415]

Answer:

Patricia will run 132 kilometers with 11 liters of gas.

Step-by-step explanation:

The given table is representing the distance driven by Patricia for every liter of gas she puts in her car.

With 3 liters of gas she drives 36 kilometers.

This means in one liter of gas distance covered by the car = \frac{36}{3}=12 kilometers.

Similarly if the car runs 48 kilometers in 4 liters of gas then per liter distance covered by the gas will be = \frac{48}{4}=12 kilometers

Now with 11 liters of gas distance covered by the car will be = 11×12

= 132 kilometers

Therefore, with 11 liters of gas Patricia can run 132 kilometers.

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1 year ago
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Triangle XYZ with vertices X(0, 0), Y(0, –2), and Z(–2, –2) is rotated to create the image triangle X'(0, 0), Y'(2, 0), and Z'(2
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Answer: The correct options are

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(D)  (x, y) → (–y, x).

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Triangle XYZ and its image triangle X'Y'Z' are shown in the attached figure.

The co-ordinates of the vertices of ΔXYZ are X(0, 0), Y(0, -2) and Z(-2, -2).

And the co-ordinates of the vertices ΔX'Y'Z' are X'(0, 0), Y'(2, 0) and Z'(2, -2).

<u>Option (A) Rotation 90°:</u>

We see from the figure that if we rotate ΔXYZ is rotated 90° anticlockwise, then it will coincide with ΔX'Y'Z'.

So, rotation of 90° anticlockwise is a correct option.

<u>Option (B) Rotation 180°:</u>

If we rotate ΔXYZ is rotated clockwise or anticlockwise 180°, then it will NOT coincide with ΔX'Y'Z'.

So, rotation of 180° is NOT a correct option.

<u>Option (C) Rotation 270°:</u>

If we rotate ΔXYZ is rotated clockwise 270°, then also it will not coincide with ΔX'Y'Z'.

So, rotation of 270° clockwise is also a correct option.

<u>Option (D) (x, y) → (–y, x):</u>

We see that the co-ordinates of both the triangle follow the transformation

X(0, 0)   ⇒  X'(0, 0)

Y(0, -2)  ⇒   Y'(2, 0)

Z(-2, -2)  ⇒   Z'(2, -2).

So, the transformation is (x, y) ⇒  (-y, x).

Therefore, the  transformation (x, y) → (–y, x) is a correct option.

<u>Option (E) (x, y) → (y, -x):</u>

We see that the co-ordinates of both the triangle does NOT follow this transformation

For example, suppose this transformation is correct. Then, we have

Y(0, -2)  ⇒  (-2, 0), which are not the co-ordinates of Y'.

Therefore, the  transformation (x, y) → (–y, x) is NOT a correct option.

Thus, the correct options are:

(A) Rotation 90° anticlockwise.

(D)  (x, y) → (–y, x).

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