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bogdanovich [222]
2 years ago
11

At full power, how long would it take for the car to accelerate from 0 to 64.0 mph ? neglect friction and air resistance. expres

s your answer in seconds.
Mathematics
1 answer:
Savatey [412]2 years ago
4 0
<span>The amount of time it would take for a car to accelerate from 0 to 64.0 mph can vary based on the vehicle. Basic vehicles generally can accelerate in under 6 seconds to 64 mph, while exotic cars can reach that speed somewhere in between 3 and 4 seconds.</span>
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Which of the following could be the ratio of the length of the longer leg of a 30-60-90 triangle to the length of its hypotenuse
Aliun [14]

Answer:

Option C is correct.

Ratio of longer leg to hypotenuse is;  \sqrt{3} : 2

Step-by-step explanation:

This is the special right angle triangle 30°-60°-90°  as shown below in the figure.

  • The side opposite the 30° angle is always the shortest because 30 degrees is the smallest angle.
  • The side opposite the 60° angle will be the longer leg, because 60 degrees is the mid-sized degree angle in this triangle.
  • Finally , the side opposite the 90° angle will always be the largest side(Hypotenuse) because 90 degrees is the largest angle.

In 30°−60°−90° right triangle,

  • the length of the hypotenuse is twice the length of the shorter leg,also
  • the length of the longer leg is \sqrt{3} times the length of the shorter leg.

Then:

the sides are in proportion i.e,  1:\sqrt{3} :2

Therefore, the ratio of the length of the longer leg to the length of its hypotenuse is:  \sqrt{3} : 2



7 0
2 years ago
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The monthly salary of Mr. Sachdev gets increased by 5%, thereby his salary becomes Rs. 15,120 per annum, His earlier monthly sal
Elan Coil [88]
1. x = 15120/12 = 1260 (monthly salary)
2. 1200 x 0.05 = 60 (raise)
Check: 1200+60=1260
6 0
2 years ago
The chart indicates the time, speed, and velocity of five runners.
Nuetrik [128]
<span>Garreth and Elisa ran together, Luigi and Jasmine went the same distance, and Logan and Jasmine have the same displacement in the opposite direction. This is the answer which is C</span>
5 0
2 years ago
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In a class of 30 students (x+10) study algebra, (10x+3) study statistics, 4 study both algebra and statistics. 2x study only alg
Vladimir [108]

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

6 0
2 years ago
If sin(x) = 1/3 and sec(y) = 25/24 , where x and y lie between 0 and π/2, evaluate the expression using trigonometric identities
Dominik [7]
<span>sin(x-y) = (24-14*sqrt(2))/75 Write down what you know sin(x) = 1/3 sec(y) = 25/24 cos(y) = 1/sec(y) = 24/25 cos(x) = sqrt(1-sin(x)^2) = sqrt(1-1/9) = sqrt(8/9) = 2*sqrt(2)/3 sin(y) = sqrt(1-cos(y)^2) = sqrt(1-576/625) = sqrt(49/625) = 7/25 We now know the sin and cos of both x and y. Now to get the sin of x-y. sin(x-y) = sin(x)cos(y) - cos(x)sin(y) Substitute the known values for sin and cos of x and y, then evaluate and simplify sin(x-y) = (1/3)(24/25) - (2*sqrt(2)/3)(7/25) sin(x-y) = 24/75 - 14*sqrt(2)/75 sin(x-y) = (24-14*sqrt(2))/75</span>
5 0
2 years ago
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