At full power, how long would it take for the car to accelerate from 0 to 64.0 mph ? neglect friction and air resistance. expres
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Answer:
The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.
Step-by-step explanation:
The data provided is as follows:
25 to 34 45 to 54
1329 2268
1906 1965
2426 1149
1826 1591
1239 1682
1514 1851
1937 1367
1454 2158
Compute the mean and standard deviation for the group "25 to 34" as follows:
Compute the <em>z</em>-score for the group "25 to 34" as follows:
Compute the mean and standard deviation for the group "45 to 54" as follows:
Compute the <em>z</em>-score for the group "45 to 54" as follows:
Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.
Find the z-scores for the two scores in the given interval.
For the score x =391,
.
For the score x = 486,
Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.
For the score x =391,
For the score x = 486,
Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.
Answer: 0.0129
Step-by-step explanation:
Given : Mean :
Standard deviation :
Sample size :
Let X be the random variable that represents the age of of the fleets.
Z-score :
For x = 14
By using standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be
Hence, the the probability that the average age of these 40 airplanes is at least 14 years old =0.0129