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pishuonlain [190]
2 years ago
14

Carys is checking her tax bill for the last year. The tax rates were as follows: No tax of the first £11 000 of earnings. Earnin

gs in excess of of £11 000 and up to £43 000 taxed at a rate of 20%. Earnings in excess of £43 000 and up to £150 000 taxed at a rate of 40%. Earnings over £150 000 taxed at a rate of 45%. Last year Carys, earned £45 600 before tax. How much tax did she pay in total. Show your working.
It isn't £18240 it says its wrong
Mathematics
2 answers:
11Alexandr11 [23.1K]2 years ago
6 0
£11000 is the tax free allowance, so we deduct 11000 from 45600=34600. This qualifies for the 40% rate. That comes to £13,840.
KatRina [158]2 years ago
3 0

Answer:

total tax is = 14685 pound

Step-by-step explanation:

Given data:

For first year -  

earning is 11000 pound

for second year

income is = 43000 - 11000 = 32000 pound

tax rate = 20%

for third year

income is = 150000 - 43000 = 107000 pound

tax rate = 40%

for fourth year

income is = 158900 - 150000 = 8900 pound

tax rate = 45%

As it is given there is no tax on first year

Tax in 2nd year  = 0.20 × 32000 = 6400 pound

Tax in 3rd year  = 0.40 × 107000 = 42800 pound

Tax in 4th year  = 0.45 × 8900 = 4005 pound

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Line segment JL is an altitude in triangle JKM. Which statement explains whether JKM is a right triangle? Round measures to the
natulia [17]

Answer:

C. JKM is not a right triangle because KM ≠ 15.3.

Step-by-step explanation:

We can see from our diagram that triangle JKM is divided into right triangles JLM and JLK.  

In order to triangle JKM be a right triangle KM^{2}=JK^{2}+JM^{2}.

We will find length of side KM using our right triangles JLM and JLK as KM=KL+LM.  

Using Pythagorean theorem in triangle JLM we will get,

LM=\sqrt{JM^{2}-JL^{2}}

LM=\sqrt{8^{2}-5^{2}}

LM=\sqrt{64-25}

LM=\sqrt{39}=6.244997998\approx 6.24

Now let us find length of side KL.

KL=\sqrt{JK^{2}-JL^{2}}  

KL=\sqrt{13^{2}-5^{2}}

KL=\sqrt{169-25}

KL=\sqrt{144}=12

Now let us find length of KM by adding lengths of KL and LM.

KM=12+6.24=18.24

Now let us find whether JKM is right triangle or not using Pythagorean theorem.

KM^{2}=JK^{2}+JM^{2}  

18.24^{2}=13^{2}+8^{2}

18.24^{2}=169+64

18.24^{2}=233

Upon taking square root of both sides of equation we will get,

18.24\neq 15.264337522473748

18.2\neq 15.3  

We have seen that KM equals 18.2 and in order to JKM be a right triangle KM must be equal to 15.3, therefore, JKM is not a right triangle and option C is the correct choice.    

6 0
1 year ago
Read 2 more answers
The vertex of this parabola is at (2,-4). When the y value is -3, the x-value is
marusya05 [52]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} h=2\\ k=-4 \end{cases}\implies y=a(x-2)^2-4 \\\\\\ \textit{we also know that } \begin{cases} y = -3\\ x = -3 \end{cases}\implies -3=a(-3-2)^2-4\implies 1=a(-5)^2 \\\\\\ 1=25a\implies \boxed{\cfrac{1}{25}=a}

4 0
2 years ago
HELP! 50 POINTS!
Alexxandr [17]

(4, -1) ---> x = 4 and y = -1

If you look at the graph you can se this

Mark points (0, 2) and (8, -4) in the coordinate plane

Plot the line going through both of these points.

Read the coordinates of the intersection of the line so you can see the solution!

6 0
1 year ago
A hockey player needs to shoot a puck 55 meters from his current location to his opponent's goal to score a goal. After the shot
lorasvet [3.4K]

Answer:

The puck traveled 53.8 meters.

Step-by-step explanation:

Currently, the player is 55 meters away from the opponent's goal.

After the shot, the puck is 120 centimeters = 1.2 meters from the opponents goal.

So, this means that the puck traveled 55 - 1.2 = 53.8 meters.

5 0
1 year ago
Read 2 more answers
In triangle ABC AD/DB = CE/EB. Complete the proof showing the segment DE is parallel to segment AC.
Natasha_Volkova [10]

Answer:

1. \dfrac{AD}{DB}+1=\dfrac{CE}{EB}+1

2. Addition property of equality

Step-by-step explanation:

In triangle ABC,

\dfrac{AD}{DB}=\dfrac{CE}{EB}.

The addition property of equality states that if the same amount is added to both sides of an equation, then the equality is still true.

Use addition property of equality, add 1 to both sides of previouse equality:

\dfrac{AD}{DB}=\dfrac{CE}{EB}\\ \\\dfrac{AD}{DB}+1=\dfrac{CE}{EB}+1\\ \\\dfrac{AD+DB}{DB}=\dfrac{CE+EB}{EB}

5 0
2 years ago
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