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HACTEHA [7]
2 years ago
7

A person must score in the upper 2% of the population on an iq test to qualify for membership in mensa, the international high-i

q society (us airways attache, september 2000). there are 110,000 mensa members in 100 countries throughout the world (mensa international website, january 8, 2013). if iq scores are normally distributed with a mean of 100 and a standard deviation of 15, what score must a person have to qualify for mensa (to the nearest whole number)?
Mathematics
1 answer:
Agata [3.3K]2 years ago
4 0
<span>135 Using a standard normal table, you can look up the number of standard deviations for the 98% value which will be 2.054. Then multiply this number by the standard deviations and add that to the mean to get the desired value. So 2.054 * 15 + 100 = 130.81 Rounding to the nearest whole number gives you 131.</span>
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Jameson has $4,300 in credit card debt with 14% interest that he wants to pay off in 24 months. He will need to make monthly pay
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The answer to this question can be defined as follows:

net paid interest = $ 655. 04

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4 0
2 years ago
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Harrizon [31]
<span>(x – 8)² + (y – 9)² = 3
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By means of the AAS postulate.

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