Answer:
k = 1.3 x 10⁻³ s⁻¹
Explanation:
For a first order reaction the integrated rate law is
Ln [A]t/[A]₀ = - kt
where [A] are the concentrations of acetaldehyde in this case, t is the time and k is the rate constant.
We are given the half life for the concentration of acetaldehyde to fall to one half its original value, thus
Ln [A]t/[A]₀ = Ln 1/2[A]₀/[A]₀= Ln 1/2 = - kt
- 0.693 = - k(530s) ⇒ k = 1.3 x 10⁻³ s⁻¹
a. 0.51 moles of Mg
b. 0.25 moles of F
Explanation:
a. To find the number of moles knowing the mass we use the following formula:
number of moles = mass / molecular weight
number of moles of Mg = 12.15 / 24 = 0.51 moles
b. To find the number of moles knowing the number of atoms we use Avogadro's number to illustrate the following reasoning:
if in 1 mole of F there are 6.022 × 10²³ atoms of F
then in X moles of F there are 1.5 × 10²³ atoms of F
X = (1 × 1.5 × 10²³) / 6.022 × 10²³
X = 0.25 moles of F
Learn more about:
Avogadro's number
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Answer:
The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.
Explanation:
From the question,
Container A contains 1000 atoms
Container B contains 500 atoms
<u>The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.</u>
The reason for such is due to the difference in the concentration of the isotopes. Container A which contains higher number of atoms will have the more changes of the release of the neutron as the changes of the hitting and splitting increases as the density of the atoms increases.
<u>Thus, the atoms in the container A will therefore decay faster than the atoms in the container B. </u>
There are many compounds which contain triple bonds between two atoms. Few of the are as follow,
Nitrogen Molecule:
N₂ or :N≡N:
Cyanide Ion:
CN⁻ or [:C≡N:]⁻
Alkynes:
R-C≡C-R
Carbon Monoxide:
CO or :C≡O:
Among given compounds Alkynes belong to a class of unsaturated hydrocarbons. The carbon atom in alkyne is sp hybridized. These unsaturated hydrocarbons have their own characteristic chemical properties.
Answer:
b. The weak base of an alkaline buffer will accept hydrogen protons when a strong acid is added to the solution
d.The conjugate acid of an alkaline buffer will donate hydrogen protons when a strong base is added to the solution.
Explanation:
A buffer is a solution that resist pH change, it shows minimal change upon addition of small amount of strong acid or strong base. An alkaline buffer will have a basic pH, above 7. It is made by mixing a weak base and its salt with a strong acid. An example of an alkaline buffer is carbonate-bicarbonate buffer that is prepared using varying amount of anhydrous sodium carbonate and volume of solution of sodium bicarbonate to get pH range between 9.2 to 10.7
Within the buffer,the salt is completely ionized while the weak base is partly ionized. on addition of acid, the released protons will be removed by the bicarbonate ion to form sodium carbonate; on addition of base, the hydroxide ion released by the base will be removed by the hydrogen ions to form water and the pH remains relatively the same
