Vince has 16 beads. How many different arrays can Vince draw to represent the total number of beads he has? List the sizes of th
e arrays.
2 answers:
He can draw 3 different arrays. Just start at 1 and count up all the way to 16 and find the numbers that go into 16 evenly. Hope that helped;)
Answer:
Vince can draw 16 beads in 5 different ways.
The size of arrays:
<1, 16>
<16, 1>
<2, 8>
<8, 2>
<4, 4>
Step-by-step explanation:
Vince has 16 beads. He has to arrange them it different array form.
The array for <a, b> where "a" is the number rows and "b" is the number of columns.
16 = 1*16
16 = 16*1
16 = 2*8
16 = 8 *2
16 = 4*4
I have draw the picture for these arrays.
So Vince can draw 16 beads in 5 different ways.
The size of arrays:
<1, 16>
<16, 1>
<2, 8>
<8, 2>
<4, 4>
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Answer:
0.24
Step-by-step explanation:
Total cards = 52
Face cards = heart {K,Q,J} , Spade {K,Q,J} , Club {K,Q,J} , Diamond{K,Q,J} = 12
Now we are given that You and a friend each randomly draw a card from a standard deck.
Probability that no one getting face card:
Favorable events = total cards - face cards = 52 -12= 40
Total cards = 52
So, probability that no one is getting face card =
Now we are supposed to find the probability that at least one of you is holding a face card
So, probability = 1 - probability that no one is getting face card
=1 - 0.76
= 0.24
So, probability that at least one of you is holding a face card is 0.24