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maks197457 [2]
2 years ago
13

You and a friend each randomly draw a card from a standard deck. What is the probability that at least one of you is holding a f

ace card (jack, queen, or king)?
Mathematics
2 answers:
Andreyy892 years ago
8 0

Answer:

0.24

Step-by-step explanation:

Total cards = 52

Face cards = heart {K,Q,J} , Spade {K,Q,J} , Club {K,Q,J} , Diamond{K,Q,J} = 12

Now we are given that You and a friend each randomly draw a card from a standard deck.

Probability that no one getting face card:

Favorable events = total cards - face cards = 52 -12= 40

Total cards = 52

So, probability that no one is getting face card = \frac{40}{52} =0.76

Now we are supposed to find the probability that at least one of you is holding a face card

So, probability = 1 - probability that no one is getting face card

                        =1 - 0.76

                        = 0.24

So, probability that at least one of you is holding a face card is 0.24

inn [45]2 years ago
4 0

Answer:

The answer is D. 7/13

Step-by-step explanation:

Just took this and this was the answer

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Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]        

Width for n = 64:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision

5 0
2 years ago
Read 2 more answers
. Steve drove for 812 hours at 72 miles per hour. How much distance did he travel?
Mazyrski [523]

Answer:

58464

Step-by-step explanation:

Multiply the two numbers

4 0
2 years ago
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Simplify: −3x(4x − 5xy + 8y)
777dan777 [17]

Answer:

-12x - 9xy

Step-by-step explanation:

-3x(4x - 5xy + 8y)

distribute

-12x + <u>15xy - 24xy</u>

combine like terms

-12x - 9xy

3 0
2 years ago
Para ingresar a la Universidad del Chocó se aplica una prueba de razonamiento que consta de 30 preguntas. Por cada respuesta cor
s2008m [1.1K]

Complete question:

Para ingresar a la Universidad del Chocó se aplica una prueba de razonamiento que consta de 30 preguntas. Por cada respuesta correcta se asignan 5 puntos y por cada incorrecta (o no contestada) se restan 2 puntos. Si un participante obtuvo un puntaje de 94 puntos, ¿cuantas preguntas respondió bien?

Responder:

número de respuestas correctas = 22

Explicación paso a paso:

Dado lo siguiente:

Número total de preguntas = 30

Deje respuestas correctas = y; Respuestas incorrectas = n

Marca otorgada por y = 5

Marca deducida por n = 2

Si el total de preguntas = 30; luego

y + n = 30 - - - - (1)

Puntuación total obtenida = 94; luego

5y - 2n = 94 - - - (2)

De 1),

y + n = 30

y = 30 - n

Sustituya y = 30 - n en equ (2)

5 (30 - n) - 2n = 94

150 - 5n - 2n = 94

150 - 7n = 94

-7n = 94-150

-7n = - 56

n = 56/7

n = 8

Sustituir n = 8 en (1)

y + n = 30

y + 8 = 30

y = 30 - 8

y = 22

y = número de respuestas correctas = 22

n = número de respuestas incorrectas = 8

3 0
2 years ago
The star aldebaran, visible from earth, lies about 65 light years away from us. What is the minimum amount of time that would be
makkiz [27]
A beam of light (travelling at the speed of light) would take 65 years to go and 65 years to come back from aldebaran, i.e. 130 years. You can send and receive a radio message (travelling at the speed of light, being electromagnetic radiation) taking so 130 years.
8 0
2 years ago
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