Answer:
<2.1130913087, 4.53153893518>; <−3.03108891325, −1.75>; <−0.91799760455, 2.78153893518>
Step-by-step explanation:
Bruce's vector is <5cos(90-25), 5sin(90-25)> = <5cos(65), 5sin(65)> ≈ <2.1130913087, 4.53153893518>
The wind's vector is <3.5cos(270-60), 3.5sin(270-60)> = <3.5cos(210), 3.5sin(210)> ≈ <−3.03108891325, −1.75>
You add them together to find his actual motion:
<−0.91799760455, 2.78153893518>
Answer:
We cant see the question
Step-by-step explanation:
You cant post images because we can't see them
Answer:
The first, second to last and last stements are true
Step-by-step explanation:
You times 8 by the percentage as
e.g 8 x 1.50 = 12 is the same as marked up by 50%
e.g 8 x 1.70 =13.6 is the same as marked up by 70%
Answer:
The cost is $9.70 per kilogram.
Step-by-step explanation:
This can be solved by a rule of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.
Solution:
The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:
1 pound - xkg
2.2 pound - 1 kg


kg
Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?
$4.40 - 0.45kg
$x - 1kg



The cost is $9.70 per kilogram.
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :

For a square , 
⇒ 
⇒ 
⇒ 
⇒ 
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.