Answer:
c. Physical adaptations to the environment drive the distribution of all three species in the wild.
Explanation:
Options A and B refer to competition between species. The experiment was about the colonizing ability of the three species, and not the interaction among them. So these two options are not correct.
Option D states that species A is better adapted to the upper intertidal zone than the middle or lower. But the table shows that species A is equally adapted to colonize upper and middle intertidal zone, and less adapted to colonize lower zones.
The correct option is C. When these competing species coexist, this is because of niche partitioning or niche differentiation. If there is not any differentiation between them, the dominant species displaces the weak species. In the exposed example, the three species coexist in the middle and lower zones, which means that they probably have different niches and got adapted to living to their environments. This adaptation to different conditions is what leads to their distribution.
In the exposed example, species A and B can live in the upper intertidal zone, where species C can not live because they can not tolerate environmental conditions. The three species can live in the middle zone, but still, A and B are more adapted to this area than C. Among A and B, B is the most adapted to living in the upper and middle zones. Species C seems to be very adapted to live in the lower intertidal zone, where species A and B can also live, but are less adapted to this area, probably due to environmental conditions or due to their vulnerability to predation. In this last area, species A is less adapted.
Answer:
the correct answer is A. a reflector that is bright in color and smooth.
Answer:
the answer for this question is seed
Explanation:
Answer:
are hydrogen, oxygen, nitrogen, and carbon,
Explanation:
which together make up over 99% of the mass of most cells. They are the lightest elements capable of forming one, two, three, and four bonds, respectively
