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il63 [147K]
2 years ago
14

Jaclyn has $120 saved and earns $40 each month in allowance. Pedro has $180 saved and earns $20 a month in allowance. If they bo

th save their entire allowances, how long will it take before Jaclyn and Pedro have saved the same amount of money?

Mathematics
1 answer:
stich3 [128]2 years ago
6 0
First, let's make an equation as to how to find how much money they have altogether:

(M stands for the # of month)

Jaclyn: 120 + 40m 
Pedro: 180 + 20m

So let's plug-in 1 for m (1 will stand for 1 month)

Jaclyn: 120 + 40 * 1 = 160
Pedro: 180 + 20 * 1 = 200

I made a table depicting how much they'll make for the next 5 months (attached below). According to that, on month 3, they will have made the same amount of money (or $240).

So they will have the same amount of money in 3 months. Hope this helps! :)

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igor_vitrenko [27]
Darryl:
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Equation:
A = P(1 + rt)

Lori:

Answer:
A = $1,932.00

(I = A - P = $532.00)

Equation:
A = P(1 + rt)

Thus $532-$405= $127 more in Lori's account
3 0
2 years ago
Read 2 more answers
The Big River Casino is advertising a new digital lottery-style game called Instant Lotto. The player can win the following mone
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Answer:

(a) The expected value of the prize for one play of Instant Lotto is $3.50.

(b) The probability that the visitor wins some prize at least twice in the 20 free plays is 0.2641.

(c) The probability that a randomly selected day has at least 1000 people play Instant Lotto is 0.2579.

Step-by-step explanation:

(a)

The probability distribution of the monetary prizes that can be won at the game called Instant Lotto is:

<em>X</em>         P (<em>X</em> = <em>x</em>)

$10        0.05

$15        0.04

$30       0.03

$50       0.01

$1000   0.001

$0         0.869

___________

Total =   1.000

Compute the expected value of the prize for one play of Instant Lotto as follows:

E(X)=\sum x\cdot P (X=x)

         =(10\times 0.05)+(15\times 0.04)+(30\times 0.03) \\+ (50\times 0.01)+(1000\times 0.001)+(0\times 0.869)\\=0.5+0.6+0.9+0.5+1+0\\=3.5          

Thus, the expected value of the prize for one play of Instant Lotto is $3.50.

(b)

Let <em>X</em> = number of times a visitor wins some prize.

A visitor to the casino is given <em>n</em> = 20 free plays of Instant Lotto.

The probability that a visitor wins at any of the 20 free plays is, <em>p</em> = 1/20 = 0.05.

The event of a visitor winning at a random free play is independent of the others.

The random variable <em>X</em> follows Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.05.

Compute the probability that the visitor wins some prize at least twice in the 20 free plays as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-[{20\choose 0}0.05^{0}(1-0.05)^{20-0}]-[{20\choose 1}0.05^{1}(1-0.05)^{20-1}]\\=1-0.3585-0.3774\\=0.2641

Thus, the probability that the visitor wins some prize at least twice in the 20 free plays is 0.2641.

(c)

Let <em>X</em> = number of people who play Instant Lotto each day.

The random variable <em>X</em> is normally distributed with a mean, <em>μ</em> = 800 people and a standard deviation, <em>μ</em> = 310 people.

Compute the probability that a randomly selected day has at least 1000 people play Instant Lotto as follows:

Apply continuity correction:

P (X ≥ 1000) = P (X > 1000 + 0.50)

                    = P (X > 1000.50)

                    =P(\frac{X-\mu}{\sigma}>\frac{1000.50-800}{310})

                    =P(Z>0.65)\\=1-P(Z

Thus, the probability that a randomly selected day has at least 1000 people play Instant Lotto is 0.2579.

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2 years ago
The pizza shop offers a 15 percent discount for veterans and senior citizens. If the price of a pizza is $12, how would you find
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I hope this helps


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2 years ago
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It’s incorrect.

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2 years ago
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What are the possible polynomial expression for dimensions of the cuboid whose volume is 12y2 + 8y -20
bogdanovich [222]

Answer:

The answer is below

Step-by-step explanation:

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Since the volume is given by the expression 12y² + 8y - 20. That is:

Volume = 12y² + 8y - 20 = 4(3y² + 2y - 5) = 4(3y² + 5y - 3y -5) = 4[y(3y + 5) -1(3y + 5)]

Volume = 4(y-1)(3y+5)

Or

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Volume = 2(y-1)(6y+10)

Therefore the dimensions of the cuboid are either 4, y-1 and 3y+5 or 2, y-1 and 6y+10

3 0
2 years ago
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