Three books (x, y, and z) rest on a table. x is on table, while y is stacked upon x, and z is stacked upon y. the weights of the
books are mx = 4 n, my = 10 n and mz = 5 n. the net force acting on book y is:
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Answer:
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given first random sample size n₁ = 500</em>
Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.
<em>First sample proportion </em>
<em> </em>
<em>Given second sample size n₂ = 700</em>
<em>Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.</em>
<em>second sample proportion </em>
<em> </em>
<em>Level of significance = α = 0.05</em>
<em>critical value = 1.96</em>
<u><em>Step(ii)</em></u><em>:-</em>
<em>Null hypothesis : H₀: There is no significance difference between these proportions</em>
<em>Alternative Hypothesis :H₁: There is significance difference between these proportions</em>
<em>Test statistic </em>
<em></em><em></em>
<em>where </em>
<em> </em><em></em>
<em> Q = 1 - P = 1 - 0.165 = 0.835</em>
<em></em><em></em>
<em>Z = -2.76</em>
<em>|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance</em>
<em>Null hypothesis is rejected at 0.05 level of significance</em>
<em>Alternative hypothesis is accepted at 0.05 level of significance</em>
<u><em>Conclusion:</em></u><em>-</em>
<em>There is there is a difference between these proportions at α = 0.05</em>