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OverLord2011 [107]

2 years ago

9

A town's population has been growing linearly. In 2003, the population was 45,000, and the population has been growing by 1700 p

eople each year. Write an equation,   , Pt for the population t years after 2003.

1 answer:

Artemon [7]2 years ago

3 0

The awnswer would be
pt=45000 + t(1700)

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You are a school photographer taking individual and class pictures for 2 classes of 21 students each. On average, each individua

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A professor uses a video camera to record the motion of an object falling from a height of 250 meters. The function f(x) = –5x2

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The answer is approximately 5.09 seconds.

Step-by-step explanation:

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f(x) = -5x^2 + 250

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8) Write an absolute value equation that has 5 and 15 as its solutions?

marissa [1.9K]

(I'm going to use brackets as my absolute value bars lol)
[5 x -3]
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2 years ago

The number of bacteria in a petri dish on the first day was 113 cells. If the number of bacteria increase at a rate of 82% per d

Tresset [83]

Answer:

4107 cells

Step-by-step explanation:

From the question, we have the following values:

Day 1 : 113 cells

Number of cells increases by day by 82%

Hence,

Day 2

113 × 82% = 92.66cells

Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells

Day 3

205.66 × 82% = 168.6412 cells

Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells

Day 4

374.3012 × 82% = 306.926984 cells

Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells

Day 5

681.228184 × 82% = 558.60711088 cells

Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells

Day 6

1239.8352949 × 82% = 1016.6649418 cells

Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells

Day 7

2256.5002367 × 82% = 1850.3301941 cells

Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells

Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells

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2 years ago