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2 years ago

Which of the following equations is equivalent to 4[x + 2(3x – 7)] = 22x – 65?

Mathematics

2 answers:

fgiga [73]2 years ago

5 0

4[x + 2(3x - 7)] = 22x - 65

4[x + 6x - 14] = 22x - 65

4x + 24x - 56 = 22x - 65

28x - 56 = 22x - 65

umka2103 [35]2 years ago

4 0

Answer: $28x-56= 22x - 65$

Step-by-step explanation:

The given expression: $4[x + 2(3x - 7)] = 22x - 65$

Consider L.H.S. $4[x + 2(3x -7)]$

Solving the bracket present inside by using distributive property, we get

$4[x + 6x -14]=4[7x-14]$

Now, Multiplying 4 inside the bracket by using distributive property:-

$28x-56$

Hence, the given function is equivalent to $28x-56= 22x -65$

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Step-by-step explanation:

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