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maks197457 [2]
2 years ago
5

The halogens, alkali metals, and alkaline earth metals have __________ valence electrons, respectively.

Chemistry
1 answer:
natima [27]2 years ago
8 0
The valence electrons are as follows for these groups of elements:

Halogen- SEVEN  (halogens are group 7 elements that need one electron for the octet rule to be achieved)

Alkali Metals - ONE  (these are group one elements that lose a single electron to form an octet and cation)

Alkaline Earth Metals - TWO (group two elements that lose two electrons to form 2+ cations)

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trans-2-Butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm-1); however, IR spectroscopy is
spayn [35]

Answer:

The other signal that would indicate the presence of a C= C bond appears close to 3100 cm^{-1}.

Explanation:

Bands that appear above 3000 cm^{-1}  are often unsaturation diagnoses suggest. The band at 3000- 3100 cm^{-1} is characteristics for C-H stretching frequencies and normally is overlaps with the ones for alkanes because it is a band of weak intensity.

4 0
2 years ago
The molar concentration of a sugar solution in an open beaker has been determined to be 0.3M. Calculate the solute potential at
antoniya [11.8K]

Answer:

- 7.48

Explanation:

Given:

Concentration of the sugar solution, C = 0.3 M

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Now,

The solute potential is given as:

solute potential = - iCRT

where,

i is the number of particles the particular molecule will make in water

i = 1 for sugar

R is the universal gas constant = 0.0831 liter bar/mole-K

on substituting the respective values, we get

solute potential = - 1 × 0.3 × 0.0831 × 300

or

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8 0
2 years ago
How many sulfur atoms would be present in 41.8 moles of sulfur?
Montano1993 [528]

Answer:

2.51 x 10*25 atoms

6 0
2 years ago
vanadium has an atomic mass of 50.9415 amu. it has two common isotopes.one isotopes has a mass of 50.9440 amu and a relative abu
Kaylis [27]

Explanation:

Average atomic mass of the  vanadium = 50.9415 amu

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Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

The atomic mass of isotope (II) of vanadium is 49.944 amu.

5 0
2 years ago
1. After clamping a buret to a ring stand, you notice that the set-up is tippy and unstable. What should you do to stabilize the
vampirchik [111]

Answer:

A. Move the buret clamp to a ring stand with a larger base.

Explanation:

The ring stands are used to hold burettes, light in weight to avoid loss of stability, that is why it is necessary to change the size of the ring stand so that it can support the buret that we are going to use.  It is not recommended to balance it with the hand since it would give us an inaccurate result in the titration.

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