All categories

2 years ago

According to mo theory, overlap of two s atomic orbitals produces __________.

1 answer:

4 0

The overlapping of two s atomic orbitals produces two molecular orbitals, one bonding molecular orbital and one anti-bonding molecular orbital.
Whenever two atomic orbitals overlap according to molecular orbital theory, it will produce one bonding and one anti bonding molecular orbital. Molecular orbital theory is also a way for determining molecular shape wherein electrons are not assigned to character bonds between atoms, however are dealt with as transferring underneath the effect of the nuclei within the entire molecule.

You might be interested in

The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution i

bija089 [108]

Answer:

110ml

Explanation:

Using the dilution equation, C1V1 = C2V2

Where C1 is the initial concentration of solution

C2 is final concentration of solution

V1 is intital volume of solution

V2 is final volume of solution.

From the question , C1=6M, C2=0.5M, V1=10ml, V2=?

$V2 =\frac{C1V1}{C2}$

$V2 =\frac{10*6}{0.5}$

$V2 =120ml$

volume of water added = final volume -initial volume

= 120-10

=110ml

3 0

2 years ago

A gas sample enclosed in a rigid metal container at room temperature (20.0∘C∘C) has an absolute pressure p1p1p_1. The container

choli [55]

Answer: p2 = 1.06p1

Explanation: pressure increases with temperature increase.

According to Gass law

P1/T1 = P2/T2

T1 = 20°c = 20 +273 = 293k

T2 = 40°c = 40 +373 = 313k

Therefore

P2 = P1T2/T1 = 313P2/293

P2 = 1.06P1

3 0

2 years ago

HELP HELP ASAP I WILL MARK BRAINLIEST

likoan [24]

Answer:

i cant read it

Explanation:

6 0

2 years ago

A 0.20 mol sample of MgCl2(s) and a 0.10 mol sample of KCl(s) are dissolved in water and diluted to 500 mL. What is the concentr

igor_vitrenko [27]

Answer:

1 M

Explanation:

Magnesium chloride will furnish chloride ions as:

$MgCl_2\rightarrow Mg^{2+}+2Cl^-$

Given :

Moles of magnesium chloride = 0.20 mol

Thus, moles of chlorine furnished by magnesium chloride is twice the moles of magnesium chloride as shown below:

$Moles =2\times 0.20\ moles$

Moles of chloride ions by magnesium chloride = 0.40 moles

Potassium chloride will furnish chloride ions as:

$KCl\rightarrow K^{+}+Cl^-$

Given :

Moles of potassium chloride = 0.10 moles

Thus, moles of chlorine furnished by potassium chloride is same as the moles of potassium chloride as shown below:

Moles of chloride ions by potassium chloride = 0.10 moles

Total moles = 0.40 + 0.10 moles = 0.50 moles

Given, Volume = 500 mL = 0.5 L (1 mL = 10⁻³ L)

Concentration of chloride ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Cl^-}=\frac{0.50}{0.5}$

The final concentration of chloride anion = 1 M

8 0

2 years ago

How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?

ozzi

The number of Ml of a 0.40 %w/v solution of ,nalorphine that must be injected to obtain a dose of 1.5 mg is calculated as below

since M/v% is mass of solute in grams per 100 ml

convert Mg to g
1 g = 1000 mg what about 1.5 mg =? grams
= 1.5 /1000 = 0.0015 grams

volume is therefore = 100 ( mass/ M/v%)

= 100 x( 0.0015/ 0.4) = 0.375 ML

6 0

2 years ago