The best and most correct answer among the choices provided by your question is the third choice or letter C.
The best model of a water <span>molecule would be: </span><span>Two small, plastic balls attached to a larger plastic ball by toothpicks</span>
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Answer:
Ionization energy
Electronegativity
Explanation:
-due to its smaller ionic radius....the electron in the outter most shell tends to expierence a stronger nuclear attraction...which makes it harder to remove the electron from the sodium atom
-Rubidium has lesser ionization energy because its (i) affected by its larger ionic radius which tends to lessen the nuclear attraction ...hence making it easier to remove the electron...(ii)and also by the screening effect done by the inner shells, which also tends to lessen the nuclear attraction.
Sodium has a higher electronegativity than rubidium;
Electronegativity is the charge density of electrons in an atom...in which its high when the atomic radius is smaller...
So hence due to the sodium atomic radius being smaller...it tends to have a higher charge density than rubidium....which then gives it a higher electronegativity value
These gases very rarely react, with others and also noble gases are odourless and colourless.
Explanation:
- Noble gases will not react with anything so that is the reason why they are known as an inert gas.
- Noble gases are present in group 18 on the periodic table and following the rule of the octet which is they completed their orbital by s2p6 which is the highest energy level.
- Most elements are discovering through their reactivity with the other elements, commonly with oxygen. In the case of a noble gas, it is difficult for a scientist to work with the gases which have very less or no chemical property in terms of their reactivity.
Answer:
100.52
Explanation:
from the ideal gas equation PV=nRT
for a given container filled with any ideal gas P and V remains constant.So T is also constant.R is as such a constant.
So n i.e no of moles will also be constant.
no of moles of Ar=3.224/40=0.0806
no of moles of unknown gas=0.0806
molecular wt of unknown gas=8.102/0.0806=100.52
Explanation:
Average atomic mass of the vanadium = 50.9415 amu
Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975
Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu
Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025
Atomic mass of Isotope (II) of vanadium ,m' = ?
Average atomic mass of vanadium =
m × abundance of isotope(I) + m' × abundance of isotope (II)
50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025
m'= 49.944 amu
The atomic mass of isotope (II) of vanadium is 49.944 amu.
