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sergij07 [2.7K]
2 years ago
4

The owner of a store displays a large jar of nickel and dimes and offers the value of the coins to the person who guesses how ma

ny dimes there are. If there are 1130 coins valued at 100%, how many dimes are there?
Mathematics
1 answer:
Sindrei [870]2 years ago
8 0
N = nickels; $0.05
d = dimes; $0.10

\left \{ {{n + d = 1130} \atop {.05n + .1d = 100}} \right.

n + d = 1130
Subtract n from both sides.
d = -n + 1130

Input d into the other equation.

.05n + .1(-n + 1130) = 100
.05n - .1n + 113 = 100
-.05n + 113 = 100
Subtract 113 from both sides.
-.05n = -13
Divide both sides by -.05.
n = 260

Input n into the equation we changed earlier.

d = -260 + 1130
d = 870

There were 870 dimes and 260 nickels.

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Using four or more complete sentences, contrast race and ethnicity and provide an example of each.
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Race and Ethnicity are considered to be social constructs that enable humans to be grouped or categorized. They are sometimes used interchangeably but most argue that they are different and give them different definitions.

Race is generally used to refer to people that have the same physical characteristics such as skin color or the same texture of hair for instance Black and White/Caucasian.

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A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
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Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

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Which best describes the graph of the cubic function f(x) = x3 + x2 + x + 1?
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Option A

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<em>See attached graph for reference</em>

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Answer:

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CHECK THE ATTACHMENT FOR DETAILED FIGURE

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