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Julli [10]
2 years ago
11

A new car is purchased for 20800 dollars. the value of the car depreciates at 10.75% per year. What will the value of the car be

, to the nearest cent, after 13 years?
Mathematics
2 answers:
labwork [276]2 years ago
7 0
The answer is 29,068 cause you to do I =p•r•t
NeX [460]2 years ago
6 0

Answer: $4742.10

Step-by-step explanation:

Exponential depreciation formula :-

y=A(1-r)^t , where y is the value of good after t years , r is rate of depreciation and A is the initial value.

Given : A= $20800  ; r=10.75%=0.1075  

The equation models this situation:

y=20800(1-0.1075)^t=20800(0.8925)^t

Then, the value of car after t=13 years :-

y=20800(0.8925)^{13}=4742.09507708\approx4742.10

Hence, the value of car after 13 years = $4742.10

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An equiangular triangle has one side of length six inches. What is the height of the triangle, drawn from that side, to the near
tino4ka555 [31]

Answer:

The height of the triangle is 5.2 inches

Step-by-step explanation:

we know that

An <u>equiangular triangle</u> is a triangle where all three interior angles are equal in measure

Remember that an equilateral triangle has three equal sides and three equal interior angles

so

An equiangular triangle Is the same that an equilateral triangle. The measure of its interior angles is equal to 60 degrees

Let

h ----> the height of triangle

b ---> the length side of the triangle

Applying Pythagoras Theorem

h^2=b^2-(b/2)^2

we have

b=6\ in

substitute

h^2=6^2-(6/2)^2

h^2=36-9

h^2=27

h=\sqrt{27}\ in

h=5.2\ in

see the attached figure to better understand the problem

5 0
2 years ago
Which transformation of AB will produce a line segment A’B that is parallel to AB
tangare [24]

Answer:

Step-by-step explanation:

A

7 0
2 years ago
Melissa is planning a rectangular vegetable garden with a square patch for tomatoes. She wants the length of the garden to excee
aivan3 [116]

Answer: 8x + 14

Step-by-step explanation:

3x + 2 + 3x + 2 + x + 5 + x + 5 = 2(4x + 7) = 8x + 14

3 0
2 years ago
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
babunello [35]

For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • <em>g: acceleration of gravity </em>
  • <em>vo: initial speed </em>
  • <em>h0: initial height </em>

For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

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t = 29 (\frac {12} {19})\\t = 18.31s

Answer:

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6 0
2 years ago
Read 2 more answers
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Ierofanga [76]
For an acute angled triangle 

h^2 < x^2 + y^2      where h = longest side and x and y are the other 2 sides.

so here we have

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15^2 <  5x^2

x^2 >  15*3 = 45
x > sqrt 45 or x > 6.7

So smallest whole number value of  x is 7
7 0
2 years ago
Read 2 more answers
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