Answer:
the ball will move towards the big bully
Answer:
Each specific property of motif and domain is explained.
Explanation:
Domain;
- May retain a 3D structure when separated from rest of the protein.
- Unit of tertiary structure because alpha helix and beta sheets are units of secondary structure.
- Stable globular units like pyruvate kinase
- May be distinct functional units in a protein
Motif;
- Repetetive supersecondary structure because they contain cluster of secondary structure.
- Beta Alpha Beta unit is an example of motif
- Clusters of secondary structure
Both Motif and Domain;
- Stabilized by hydrophobic interactions like hydrogen bonding stabilize the both.
- Depends on primary structure like the arrangement of amino acid in polypeptide chain determine the secondary and tertiary structure of proteins.
Although the process varies slightly from one material to another, the general process is as follows:
1) Choose an appropriate container for the solid. This may be a petri dish or a beaker in which you want to prepare the solution of the solid or any other lab equipment.
2) Place the container on a mass balance, then turn the balance on. The mass balance will automatically zero-out the mass of the container, so that any mass that you add on the container will be the mass of the solid. Alternatively, you may first measure the mass of the empty container alone.
3) Add the solid using a lab spatula. The solid should be added more slowly when the reading on the scale comes close to the desired value.
4) Remove the container from the mass balance after the desired amount of solid has been added.
the equation is p1 x v1 divided by T1 = p1 x v2 = T2 but since the pressure is kept constant you do not even need it so the equation would now be v1 divided by t1 = v2 divided by t2
2135 cm3 divided by 127 degrees celcius = x divided by 206
answer: 3460 cm3
Answer:
- 0.0249% Sb/cm

Explanation:
Given that:
One surface contains 1 Sb atom per 10⁸ Si atoms and the other surface contains 500 Sb atoms per 10⁸ Si atoms.
The concentration gradient in atomic percent (%) Sb per cm can be calculated as follows:
The difference in concentration = 
The distance
= 0.2-mm = 0.02 cm
Now, the concentration of silicon at one surface containing 1 Sb atom per 10⁸ silicon atoms and at the outer surface that has 500 Sb atom per 10⁸ silicon atoms can be calculated as follows:

= - 0.0249% Sb/cm
b) The concentration
of Sb in atom/cm³ for the surface of 1 Sb atoms can be calculated by using the formula:

Lattice parameter = 5.4307 Å; To cm ; we have
= 

= 
The concentration
of Sb in atom/cm³ for the surface of 500 Sb can be calculated as follows:

= 
= 
Finally, to calculate the concentration gradient


