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Aleonysh [2.5K]
2 years ago
3

Suppose the isotope your skittles® represented was uranium-238 and the trials represent the number of half-lives. how old was th

e sample at the end of your tests? use table 1 in the introduction to help you answer this question. include your calculations. 3. if 1/8 of a radioactive element remains after 600 years, what is that element's half-life? 4. identify and describe similarities and differences between this experiment and radioactive decay in nature.
Chemistry
1 answer:
Sonja [21]2 years ago
7 0
I can't answer the first and the last question because no given data is provided. However, I can answer the second question.

<span>if 1/8 of a radioactive element remains after 600 years, what is that element's half-life? 

The formula for half life, t1/2, is:
t1/2 = ln2/K

So we must determine K first. The formula for that is:
A = A</span>₀e^(-kt)
where
A = 1/8*A₀
t = 600 years
Thus,
1/8*A₀ = A₀e^(-k*600)
1/8 = e^(-600k)
Solving for k,
K = 3.466×10⁻³

Therefore,
t1/2 = ln2/3.466×10⁻³ = <em>200 years</em>
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Analyze: The first shell can hold a maximum of two electrons. How does this explain the valence of hydrogen
chubhunter [2.5K]

Answer:

See explanation

Explanation:

Hydrogen has a valency of +1 or -1. Its electronic configuration is 1s1.

The 1s sub-level (first shell) is known to hold two electrons. This means that hydrogen may either loose this one electron in the 1s level to yield H^+ or accept another electron into this 1s level to form H^- (the hydride ion).

The formation of the hydride ion completes the 1s orbital.

4 0
2 years ago
Consider the balanced equation below. 4NH3 + 3O2 --&gt; 2N2 + 6H2O What is the mole ratio of NH3 to N2?
AURORKA [14]
The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

From this equation, we can note that 4 moles of NH3 are required to produce 2 moles of N2.

Therefore, the mole ratio of NH3 to N2 is 4:2 which can be simplified into 2:1
4 0
2 years ago
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A 15.0-L rigid container was charged with 0.500 atm of kryp‑ ton gas and 1.50 atm of chlorine gas at 350.8C. The krypton and chl
Alecsey [184]

Answer: 32.94 g

Explanation: It's stoichiometry problem so balanced equation is required. The balanced equation is given below:

Kr+2Cl_2\rightarrow KrCl_4

From the balanced equation, krypton and chlorine react in 1:2 mol ratio. We will calculate the moles of each reactant gas using ideal gas law equation(PV = nRT) and then using mol ratio the limiting reactant is figured out that helps to calculate the amount of the product formed.

for Krypton, P = 0.500 atm and for chlorine, P = 1.50 atm

V = 15.0 L

T = 350.8 + 273 = 623.8 K

For krypton, n=\frac{0.500*15.0}{0.0821*623.8}

n = 0.146 moles

for chlorine, n=\frac{1.50*15.0}{0.0821*623.8}

n = 0.439

From the mole ratio, 1 mol of krypton reacts with 2 moles of chlorine. So 0.146 moles of krypton will react with 2 x 0.146 = 0.292 moles of chlorine.

Since 0.439 moles of chlorine are available, it is present in excess and hence the limiting reactant is krypton.

So, the amount of product formed is calculated from moles of krypton.

Molar mass of krypton tetrachloride is 225.61 gram per mol.

There is 1:1 mol ratio between krypton and krypton tetrachloride.

0.146molKr(\frac{1molKrCl_4}{molKr})(\frac{225.61gKrCl_4}{1molKrCl_4})

= 32.94 g of KrCl_4

So, 32.94 g of the product will form.

5 0
2 years ago
Why it is impossible for an isolated atom to exist in the hybridized state?
kakasveta [241]

Hybridization refers to the mixing of atomic orbitals in an atom. The number of hybrid orbitals needs to be equal to the number of orbitals that have involved in prior to mixing.  

The isolated atoms cannot prevail in a hybridized state as the atom in an isolated state do not form any kind of bond with the other atom, due to which the atomic orbitals do not go through the process of hybridization.  


7 0
2 years ago
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