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2 years ago

6 pounds of tomatoes cost $8.88. At this same rate, how much do 4 pounds of tomatoes cost?

2 answers:

7 0

To find your answer you must divide $8.88 by 6 to get the amount of what one pound of tomatoes is. Then you multiply that by 4 pounds to get the answer you want. Equation- $8.88/6= $1.48. $1.48*4=5.92. Therefore your answer is $5.92.
Brainliest?

kolbaska11 [484]2 years ago

7 0

Answer:

Brainliest?

Step-by-step explanation:

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Which problem can be represented by the equation 12z + 2= 98

lisabon 2012 [21]

Where are the problems?

8 0

1 year ago

Suppose that 90% of all dialysis patients will survive for at least 5 years. In a simple random sample of 100 new dialysis patie

Keith_Richards [23]

Answer:

The probability $P(\^ p > 0.80) = 0.99957$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.90

The sample size is n = 30

Generally mean of the sampling distribution is $\mu_{\= x } = p = 0.90$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{p( -p )}{n} }$

=> $\sigma = \sqrt{\frac{0.90( 1 -0.90 )}{100} }$

=> $\sigma = 0.03$

Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

$P(\^ p > 0.80) = P(\frac{ \^ p - p }{ \sigma } > \frac{0.80 - 0.90}{0.03} )$

Generally $\frac{\^p - p}{\sigma} = Z(The standardized \ value \ of \^ p)$

$P(\^ p > 0.80) = P(Z > -3.33 )$

From the z-table $P(Z > -3.33 ) = 0.99957$

$P(\^ p > 0.80) = 0.99957$

5 0

2 years ago

Solve the following quadratic equations by extracting square roots.Answer the questions that follow.

Vikentia [17]

Answer:

1. x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

Taking square root on both sides

$\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\$

x=±4

2. t^2=81

Taking square root on both sides

$\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}$

t=±9

3. r^2-100=0

$r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}$

r=±10

4. x²-144=0

x²=144

Taking square root on both sides

$\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}$

x=±12

5. 2s²=50

$\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}$

s=±5 ..

4 0

1 year ago

Read 2 more answers

A 22.5 ounce candle burns at the rate of one ounce every 5 hours. write an equation for the amount of candle left

maks197457 [2]

Answer:

y = 22.5 - 0.2t

Step-by-step explanation:

Given;

total number of candle, n = 22.5 ounce

Rate of candle burn, R = 1 ounce per 5 hours $= \frac{1 \ ounce}{5 \ hours} = 0.2 \ \frac{ounce}{hour}$

The amount of candle left = total initial value - amount burnt

let the amount let = y

y = 22.5 - 0.2t

where;

t is the time in which the candle is burnt

Thus, the equation for the amount of candle left is given by;

y = 22.5 - 0.2t

7 0

1 year ago

What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1

marta [7]

First, we need to solve the differential equation.
$\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)$
This a separable ODE. We can rewrite it like this:
$-\frac{4}{y^2-8y}{dy}=dt$
Now we integrate both sides.
$\int \:-\frac{4}{y^2-8y}dy=\int \:dt$
We get:
$\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1$
When we solve for y we get our solution:
$y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}$
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8$
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.

3 0

1 year ago