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marissa [1.9K]
2 years ago
5

Chelsea made monthly payments for four years before her $13,440 loan was paid off. The loan had an interest rate of 5.86%, compo

unded monthly. Chelsea paid $156.60 in service charges. To the nearest tenth, what percentage of the total cost of the loan did her finance charges comprise? Round all dollar values to the nearest cent. a. 13.6% b. 10.9% c. 9.4% d. 11.9%
Mathematics
2 answers:
Margarita [4]2 years ago
8 0

Answer:

Option A - 13.6%

Step-by-step explanation:

Given : Chelsea made monthly payments for four years before her $13,440 loan was paid off. The loan had an interest rate of 5.86%, compounded monthly.

Chelsea paid $156.60 in service charges.

To find : Percentage of the total cost of the loan did her finance charges comprise?

Solution : First we find the monthly payment


Formula of monthly payment  

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}  

Discount factor D=\frac{1-(1+i)^{-n}}{i}  

Where, Amount = $13,440

Rate r= 5.86%=0.0586 compounded monthly

i=\frac{0.0586}{12}=0.00488  

Time = 4 years  

n=4\times12=48  

Now, put all the values we get,  

D=\frac{1-(1+i)^{-n}}{i}  

D=\frac{1-(1+0.00488)^{-48}}{0.00488}  

D=\frac{1-(1.00488)^{-48}}{0.00488}  

D=\frac{1-0.791}{0.00488}  

D=\frac{0.209}{0.00488}  

D=42.827  

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}  

M=\frac{13440}{42.827}  

M=314.77  

Monthly payment is $314.77

For 4 years or 48 months

Payment is 314.77\times48=15108.96

Total amount = Payment - Amount

Total amount = 15108.96 - 13440

Total amount = 1668.96

Cost of loan is total amount with service charges is

⇒1668.96+156.60 = $1825.56

Total cost of the loan did her finance charges comprise

\text{Total cost}=\frac{\text{Cost}}{\text{Amount}}

\text{Total cost}=\frac{1825.56}{13440}

\text{Total cost}=0.1358

Total cost in percentage 0.1358\times100=13.58\%

Approximately,Total cost of the loan did her finance charges comprise is 13.6%

Therefore, Option A is correct - 13.6%

valentinak56 [21]2 years ago
4 0
The answer is d.11.9

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