Let's simplify step-by-step.
<span><span>0.2<span>(<span><span>3b</span>−<span>15c</span></span>)</span></span>+<span>6c
</span></span>Distribute:<span>=<span><span><span><span>(0.2)</span><span>(<span>3b</span>)</span></span>+<span><span>(0.2)</span><span>(<span>−<span>15c</span></span>)</span></span></span>+<span>6c
</span></span></span><span>=<span><span><span><span>0.6b</span>+</span>−<span>3c</span></span>+<span>6c
</span></span></span>Combine Like Terms:
<span>=<span><span><span>0.6b</span>+<span>−<span>3c</span></span></span>+<span>6c
</span></span></span><span>=<span><span>(<span>0.6b</span>)</span>+<span>(<span><span>−<span>3c</span></span>+<span>6c</span></span>)
</span></span></span><span>=<span><span>0.6b</span>+<span>3<span>c</span></span></span></span>
12 1/4 feet wide stream so it is 1 feet and 9 inches shorter
Answer:
C I think
Step-by-step explanation:
Note that (5π)/6 radians = 150°. Therefore the given angle is in quadrant 2.
Refer to the figure shown below.
Reference angles are measured relative to the horizontal axis.
Therefore the reference angle in each quadrant is π/6 radians or 30°.
Denote the reference angle as θ'.
Then, in quadrant 1,
cos θ' = √3/2, sin θ' = 1/2, tan θ' = √3.
Because we are in quadrant 2,
sin θ' = π/6;
sin(5π/6) is positive, but cos (5π/6) and tan (5π/6) are negative.
Answer:
5π/6 is in quadrant 2.
The reference angle, θ' = π/6.
sin(5π/6) is positive, cosine and tangent are negative.
A conservative vector field

has curl

. In this case,

so the vector field is not conservative.