Ask question

Ask question

All categories

VladimirAG [237]

2 years ago

6

tracey bought a diamond ring appraised at$ 1600 at an antique store. if diamonds have appreciated in value at an annual rate of

10%, what was the value of the ring 10 years ago?

2 answers:

Anton [14]2 years ago

8 0

1600 / 1.1^10 = $616.87
I think I'm not sure check your answer

WINSTONCH [101]2 years ago

3 0

Hello There!

1600 / 1.1^10 = $616.87

Hope This Helps You!
Good Luck :)

- Hannah ❤

You might be interested in

Which of the following values for m proves that 2m + 2m is not equivalent to 4m2?

Mashutka [201]

M=0 i am not sure it is right

6 0

2 years ago

Read 2 more answers

7. If W = 3Z, and Z is 30% of R, then W is what

dem82 [27]

Answer:

90%

Step-by-step explanation:

Let R = 100

Since, Z = 30% of R

Therefore, Z = 30% *100 = 30

Since, W = 3Z

Therefore, W = 3*30 = 90

Percentage of W of R

$= \frac{Value \: of \: W}{Value \: of \: R} \times 100\\\\=\frac{90}{100} \times 100\\\\Percentage \:of \:W \:of \:R =90\%$

7 0

2 years ago

7. You and a friend are paid $38.25 for doing yard

nata0808 [166]

Answer:

Step-by-step explanation: your friend would get 17$

and you would get 21.25

hope this helpsss ;))))

8 0

2 years ago

Read 2 more answers

An astronomical unit (AU) is the average distance between Earth and the sun. One AU is equal to approximately 150,000,000 km. As

lozanna [386]

Answer:

Can u separate it?

Step-by-step explanation:

5 0

2 years ago

See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se

REY [17]

Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 6, p = 0.2$

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015$

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064$

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564$

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if $P(X \geq 5) < 0.05$

We have that

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05$

Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

5 0

2 years ago