A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the bo

Question

Oksana_A [137]

2 years ago

7

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the bo

x?

Physics

2 answers:

Reptile [31] · Answer 1 · 2023-07-04T07:49:42+03:00

Reptile [31]2 years ago

6 0

23.1N of force applied

Bezzdna [24] · Answer 2 · 2023-07-04T06:02:50+03:00

Bezzdna [24]2 years ago

5 0

Use this numbers that you are given and plug them into the formule for net force

Net force= m*a (mass times acceleration)

Therefore the net force is equal to (5.5 kg)*(4.2 m/s^2)= 23.1 N

Answer: Net force= 23.1 N