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vova2212 [387]
2 years ago
7

A person fishing from a pier observes that 6 wave crests pass by in 8.0 s and estimates the distance between two successive cres

ts to be 4.8 m. The timing starts with the first wave crest and ends with the last. What is the speed of the wave?
Physics
1 answer:
Talja [164]2 years ago
7 0

Answer:

The speed of the wave is 3 m/s.

Explanation:

Given that,

Number of waves = 6

Time = 8.0 s

Successive crests \lambda = 4.8\ m

We need to calculate the frequency

Using formula of frequency

f=\dfrac{Number\ of \ cycles}{t}

Put the value into the formula

f=\dfrac{6-1}{8.0}

f=0.625\ cycle/sec

We need to calculate the speed of the wave

Using formula of speed

v=\lambda\times f

Put the value into the formula

v=4.8\times0.625

v=3\ m/s

Hence, The speed of the wave is 3 m/s.

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You testify as an expert witness in a case involving an accident in which car A slid into the rear of car B, which was stopped a
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Answer:

A) 12.08 m/s

B) 19.39 m/s

Explanation:

A) Down the hill, we will apply Newton’s second law of motion in the downward direction to get:

mg(sinθ) – F_k = ma

Where; F_k is frictional force due to kinetic friction given by the formula;

F_k = (μ_k) × F_n

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Thus;

F_k = μ_k(mg cosθ)

We now have;

mg(sinθ) – μ_k(mg cosθ) = ma

Dividing through by m to get;

g(sinθ) – μ_k(g cosθ) = a

a = 9.8(sin 12.03) - 0.6(9.8 × cos 12.03)

a = -3.71 m/s²

We are told that distance d = 24.0 m and v_o = 18 m/s

Using newton's 3rd equation of motion, we have;

v = √(v_o² + 2ad)

v = √(18² + (2 × -3.71 × 24))

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B) Now, μ_k = 0.10

Thus;

a = 9.8(sin 12.03) - 0.1(9.8 × cos 12.03)

a = 1.08 m/s²

Using newton's 3rd equation of motion, we have;

v = √(v_o + 2ad)

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v = 19.39 m/s

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