Answer:A. 10x. B. -2yz
Step-by-step explanation:
A. 4x+7x=11x
11x+(-x) = 11x-1x=10x
B. -5yz+yz=-4yz
-4yz+2yz=-2yz
Um... you can't see what you need to solve the problem in the picture. Take a picture of the chart.
First of 30% of 2500kcal is 750kcal
if a male consumes 2.5 kcal then 750kcal / 2.5kcal = 300
but then we would need to know how many wheat are on one hectare of land.
Answer:

Step-by-step explanation:
Consider the given matrix
![A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D)
Let matrix B is
![B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
It is given that

![\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
On comparing corresponding elements of both matrices, we get



Therefore, the required values are
.
There are different definitions of "whole numbers".
Some define it as an integer (i.e. positive or negative) [some dictionaries]
Some define it as a non-negative integer. [most math definitions]
We will take the math definition, i.e. 0<= whole number < ∞
To find pairs (i.e. two) whole numbers with a sum of 110, we start with
0+110=110
1+109=110
2+108=110
...
54+56=110
55+55=110
Since the next one, 56+54=110 is the same pair (54,56) as 54+56=110, we stop at 55+55=110 for a total of 56 pairs.