Jordan wrote the following description: Three fewer than one four of x is 12. write an equation to represent the description.

Mathematics

2 answers:

tigry1 [53]2 years ago

8 0

The correct way to write this equation is .25x-3=12. The .25 is interchangeable with $\frac{1}{4}$

Kaylis [27]2 years ago

5 0

Start first with the coefficient of x, which will be 1/4 as you want to find 1/4 of x. Now, minus 3 to that to give you 3 fewer than 1/4x. You know this equates to 12, so your expression is:
1/4x - 3 = 12
Or you can write it like this if you want to use brackets:
1/4(x-12)=12

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Which of the following best describes the graph below?

Sonja [21]

Answer: Option A

Step-by-step explanation:

A function is one to one if every element in the range (y) has only one value in the domain (x) associated to it, while a function is many to one if some values in the range (y) have more than one element in the domain (x) associated.

In this function, we can see that the function is almost linear and always increases and it is easy to see that each value of y has only one value of x associated (because the line will always increase) the correct option is A.

8 0

2 years ago

-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz

vitfil [10]

To graph it, just graph $y=-3^{-x}-6$ and $y=-3^x+10$ and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
$3^{-x}+6=3^x-10$
multiply both sides by $3^x$
$3^0+6(3^x)=3^{2x}-10(3^x)$
$1+6(3^x)=3^{2x}-10(3^x)$
minus 1 from both sides and minus 6(3^x) from both sides
$0=3^{2x}-16(3^x)-1$
use u subsitution
$u=3^x$
we can rewrite it as
$0=u^2-16u-1$
now factor
I mean use quadratic formula
for $ax^2+bx+c=0$ $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$
so for 0=u^2-16u-1, a=1, b=-16, c=-1
$u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}$
$u=8+/-\sqrt{65}$
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
$u=8+\sqrt{65}=3^x$
$8+\sqrt{65}=3^x$
if you take the log base 3 of both sides you get
$log_3(8+\sqrt{65})=x$
if you use ln then
$ln(8+\sqrt{65})=xln(3)$
then
$\frac{ln(8+\sqrt{65})}{ln(3)}=x$