<span>Partial products are different in regrouping in terms of how numbers are clustered from a set equation as a whole delivering it individual but naturally to all the numbers involved in the set. </span>
Regrouping is just like the commutative or associative property of numbers.
<span>Associative property of addition is used when you want to group addends. This is mainly used to cluster set of numbers or in this case, addends. How do you use the associative property when you break apart addends? Simple you group them using the open and closed parentheses or brackets. Take for an example 1 + 1 + 2 = 4. Using the associative property you can have either (1 + 1) + 2 = 4 or 1 + (1 + 2) = 4 clustered into place.
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Answer: 20 unit.
Step-by-step explanation:
Since, Here the vertices of the rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0).
Where, de, ef, fg, gd are sides of the rhombus defg.
By the distance formula,





Thus, the side of rhombus = 5
By the property of rhombus,
de = ef = fg = gd = 5 unit.
Thus, the perimeter of the given rhombus defg = de + ef + fg + gd = 5+5+5+5 = 20 unit
Answer:
4 dollars to sell tamatoes
he sells 10 tomataoes
8 fruit
Step-by-step explanation:
random answer dont put it in
Answer:
1) Decimal 
2) Binary 
3) Octal 
4) Hexadecimal 
Step-by-step explanation:
Given : Integer is 25
To find : Represent integer in decimal, binary, octal, and hexadecimal formats.
Solution :
1) Integer into decimal - To convert into decimal the base goes to 10.
So, 
2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.
Divide 25 by 2 and note down the remainders.
2 | 25
2 | 12 R=1 ←
2 | 6 R=0 ↑
2 | 3 R=0 ↑
2 | 1 → R=1 ↑
So, 
3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.
Divide 25 by 8 and note down the remainders.
8 | 25
| 3 → R=1
So, 
4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.
Divide 25 by 16 and note down the remainders.
16 | 25
| 1 → R=9
So, 
Answer:
<em>When 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.</em>
Step-by-step explanation:
The Least Common Multiple ( LCM )
The LCM of two integers a,b is the smallest positive integer that is evenly divisible by both a and b.
For example:
LCM(20,8)=40
LCM(35,18)=630
Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.
Find the LCM of 4,10,12. Follow this procedure:
List prime factorization of all the numbers:
4 = 2*2
10 = 2*5
12 = 2*2*3
Multiply all the factors the greatest times they occur:
LCM=2*2*3*5=60
Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.