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Whitepunk [10]
2 years ago
10

The longer diagonal of a right trapezoid is 13 cm. The longer base is 12 cm. Find the area of the trapezoid if the shorter base

is 8 cm.
Mathematics
1 answer:
topjm [15]2 years ago
5 0
Draw a diagram of a right trapezoid . 
<span>B ---------------- C </span>
<span>.| ............ ............ * </span>
<span>.| ............ ............ ..... * </span>
<span>A --------------- -------------- D </span>
<span>Longer diagnal BD = 13cm </span>
<span>Longer base AD = 12cm </span>
<span>Shorter base BC = 8cm </span>
<span>Angle A is 90° , so △BAD is a right triangle . </span>
<span>AB^2 + AD^2 = BD^2 </span>
<span>AB^2 + 12^2 = 13^2 </span>
<span>AB^2 + 144 = 169 </span>
<span>AB^2 = 25 </span>
<span>AB = 5 </span>
<span>So the area of trapezoid ABCD is (12+8)*5/2 = 50 [cm^2] .</span>
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Answer: independent variable: time (t). Dependent variable: distance (d).

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Seamus has a truck of chairs and tables for a party. There are 8 times as many chairs as tables, for a total of 56 chairs in the
DIA [1.3K]

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Step-by-step explanation:

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2 years ago
Estimate 58% of 121 by using 10%
kvv77 [185]
58% is about equal to 60%, 10% of 121 is 12.1.
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2 years ago
Let e1= 1 0 and e2= 0 1 ​, y1= 4 5 ​, and y2= −2 7 ​, and let​ T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps
Furkat [3]

Answer:

The image of \left[\begin{array}{c}4&-4\end{array}\right] through T is \left[\begin{array}{c}24&-8\end{array}\right]

Step-by-step explanation:

We know that T: IR^{2}  → IR^{2} is a linear transformation that maps e_{1} into y_{1} ⇒

T(e_{1})=y_{1}

And also maps e_{2} into y_{2}  ⇒

T(e_{2})=y_{2}

We need to find the image of the vector \left[\begin{array}{c}4&-4\end{array}\right]

We know that exists a matrix A from IR^{2x2} (because of how T was defined) such that :

T(x)=Ax for all x ∈ IR^{2}

We can find the matrix A by applying T to a base of the domain (IR^{2}).

Notice that we have that data :

B_{IR^{2}}= {e_{1},e_{2}}

Being B_{IR^{2}} the cannonic base of IR^{2}

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]   (Data of the problem)

T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]   (Data of the problem)

Writing the matrix A :

A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]

Now with the matrix A we can find the image of \left[\begin{array}{c}4&-4\\\end{array}\right] such as :

T(x)=Ax ⇒

T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]

We found out that the image of \left[\begin{array}{c}4&-4\end{array}\right] through T is the vector \left[\begin{array}{c}24&-8\end{array}\right]

3 0
2 years ago
9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of
netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 12, \sigma = 3

What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 12}{3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

1 - 0.9082 = 0.0918

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

5 0
2 years ago
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