Answer:
The correct option is;
The ranges of f(x) and h(x) are similar and different from the ranges of g(x)
Step-by-step explanation:
Here we have the functions given as follows;
f(x) = -6/11 (11/2)ˣ
g(x) = 6/11 (11/2)⁻ˣ
h(x) = -6/11 (11/2)⁻ˣ
from the above equations, it can be seen that f(x) and h(x) are always negative while g(x) is always positive
f(x) and h(x) are symmetric about the y axis while g(x) and h(x) are symmetric about the x axis
Also h(x) is the inverse of f(x) hence the ranges of f(x) and g(x) are similar and are different from the ranges of g(x).
Let X equal the remaining time she needs to practice.
You would have 2x
The combined total needs to be 6 hours or greater.
You need to add the amount she already practiced to 2x.
Now you have: three and one fourth + 2x
This needs to be greater than or equal to 6.
Answer: three and one fourth + 2x ≥ 6
Answer:
$23,360
Step-by-step explanation:
Calculation to determine how much carol originally invested in the account
First step is to divide £23517.60 by 1.025
= (23,517.60)/(1+.025)
= (23,517.60)/1.025
=$22,944
Second step is to add back the $1,000 withdrew
=$22,944+$1,000
=$23,944
Now let calculate how much carol originally invested in the account
$23,944=1.025P
Divide both side by 1.025
P=$23,944/1.025
P=$23,360
Therefore the amount that carol originally invested in the account is $23,360
Answer:
0.0406, 0.8284,0.7887
Step-by-step explanation:
Given that Mattel Corporation produces a remote-controlled car that requires three AA batteries
X is N(34, 5.5)
Hence sample size of 25 would follow a t distribution with df = 24
This is because sample size <30
t distribution with df 24 would be bell shaped symmetrical about the mean and unimodal.
Std error of sample mean = std dev /sqrt n=
Prob (X>36) = 
i.e nearly 4.1% of the sample would have a mean useful life of more than 36 hours
X>33.5 implies 
=0.82837
=0.8284 proportion will have a mean useful life greater than 33.5 hours
Proportion between 33.5 and 36 hours
= 