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stiv31 [10]
2 years ago
3

Sarah is lining a square tray with 1 inch square tiles the side length of the tray is 9 inches how many tiles does Sarah need

Mathematics
1 answer:
kotegsom [21]2 years ago
8 0
If it's a square, both sides are equal. If one side is 9 inches, then the other side is 9 inches. When you are finding area of a quadrilateral you multiply the two different lengths together. So 9in×9in=81in^3. (^3 means a tiny 3 up at the top corner of the number).
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What are the six-digit grid coordinates for spot elevation 192
Yuliya22 [10]

Answer:

750450

Step-by-step explanation:

3 0
2 years ago
How many 4/5 cup servings are in 4/9 of a cup of yogurt
kolbaska11 [484]
For this question, you need to understand how to divide fractions.First we line up our fractions appropriately:
4/9 ÷ 4/5 = ?         (You want to divide 4/9 by 4/5)
4/9 × 5/4 = ?         (Now we use the reciprocal of 4/5 and multiply instead of divide)
4 x 5 = 20 and 9 x 4 = 36.       (Cross multiply.)
20/36 = 5/9.           (Simplify to lowest terms.)
So, 4/9 divided by 4/5 is 5/9!But 5/9 is more than 4/9, so the answer is 0 :PCorrect me if I'm wrong.
5 0
2 years ago
Read 2 more answers
According to a Los Angeles Times study of more than 1 million medical dispatches from 2007 to 2012, the 911 response time for me
Reil [10]

Answer:

a) \bar X=10.65

Median =\frac{10.7+10.7}{2}=10.7

Mode= 10.7

b) Range = 11.8-8.3=3.5

s= 0.948

c)IQR = Q_3 -Q_1 = 11.05-10.55=0.5

And we can find the usual limits with:

Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8

Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And if we replace we got: \bar X=10.65

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

Median =\frac{10.7+10.7}{2}=10.7

The mode would be the most repeated value on this case:

Mode= 10.7

Part b

The range is defined as Range =Max-Min and if we replace we got:

Range = 11.8-8.3=3.5

We can calculate the standard deviation with the following formula:

s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And if we replace we got:

s= 0.948

Part c

For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.

We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and Q_1= \frac{10.6+10.7}{2}=10.55

And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got Q_3 = \frac{10.9+11.2}{2}=11.05

Then we can find the IQR like this:

IQR = Q_3 -Q_1 = 11.05-10.55=0.5

And we can find the usual limits with:

Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8

Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

Part d

The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

6 0
2 years ago
A triangle is such that the largest angle is 7 times the smallest angle. The third angle is 15 less than the largest angle. Find
Tcecarenko [31]

Answer:

<u>The smallest angle measures 13°, the largest angle measures 91° and the third angle measures 76°</u>

Step-by-step explanation:

Let's recall that the interior angles of a triangle add up to 180°, therefore we have:

Smallest angle = x

Largest angle = 7x

Third angle = 7x - 15

Now, we can solve for x, using the following equation:

x + 7x + 7x - 15 = 180

15x = 180 + 15

15x = 195

x = 195/15

x = 13 ⇒ 7x = 91 ⇒ 7x - 15 = 76

<u>The smallest angle measures 13°, the largest angle measures 91° and the third angle measures 76°</u>

8 0
2 years ago
Susan keeps track of the number of tickets sold for each play presented at the community theater. within how many standard devia
Citrus2011 [14]
The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 )  : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
 x (Mean) - 2 s and  x + 2 s 
 
3 0
2 years ago
Read 2 more answers
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