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2 years ago

4

The science club charges $4.50 per car at their car wash. Write and solve an inequality to find how many cars they have to wash

to earn at least $300.

2 answers:

mylen [45]2 years ago

7 0

$4.50x <span>≥ </span>$300
hope this helps!

swat322 years ago

3 0

Answer:

67 cars.

Step-by-step explanation:

Let x represent number of cars.

We have been the science club charges $4.50 per car at their car wash. the amount earned for washing x cars would be $4.50x$ .

We have been given that the science club have to earn at least $300. This means that amount earned for washing x cars would be greater than or equal to 300.

We can represent this information in an inequality as:

$4.50x\geq 300$

$\frac{4.50x}{4.50}\geq \frac{300}{4.50}$

$x\geq 66.66$

Since the closest integer to 66.66 is 67, therefore, they have to wash 67 cars to earn at least $300.

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balandron [24]

Answer:

4

Step-by-step explanation:

If sandwiches are 6 dollars each, then chips are 3 dollars, she only bought 5 sandwiches for 6 each for 30 dollars(5*6=30).So, she has 12 dollars left to spend since she spent 42 dollars. And 4 *3=12so she only bought 4 bags of chips.

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Lera25 [3.4K]

Answer:

$Sum = -81$

Step-by-step explanation:

See the comment for complete question.

Given

$c = 36$ ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

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So, the equation can be represented as:

$x^2 + ax + 36 = 0$

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

$x = -\alpha$ and $x = -\beta$

Using the above roots, the equation can be represented as:

$(x + \alpha)(x + \beta) = 0$

Open brackets

$x^2 + (\alpha + \beta)x + \alpha \beta = 0$

To compare the above equation to $x^2 + ax + 36 = 0$ , we have:

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The values of $\alpha$ and $\beta$ that satisfy $\alpha \beta = 36$ are:

$\alpha = -1$ and $\beta = -36$

$\alpha = -2$ and $\beta = -18$

$\alpha = -3$ and $\beta = -12$

$\alpha = -4$ and $\beta = -9$

So, the possible values of a are:

$a = \alpha + \beta$

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$a = -3 - 12 = -15$

When $\alpha = -4$ and $\beta = -9$

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The required sum is:

$Sum = -37 -20 -15 - 9$

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Nataliya [291]

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