Julie should highlight row 2 and row 3 and use the delete command.
Answer:
"Analog" seems to be the appropriate choice.
Explanation:
- Data estimation or representation by purposes of one sometimes more physical characteristics which can convey any information on a continuum of severity.
- Analog data or information is information that is expressed physically. At which digital information is a series of individual symbols, analog data, if the substrate loops on even a vinyl record, the magnetic disks on a VCR compilation, and perhaps other non-digital material, is contained in physical media.
Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
Answer:
=(A4+B4+C4+D4+E4)/5
Explanation:
If we want to have the average of the passengers, first we must sum all the revenue and then divide it with passenger quantity.
In this particular example, I made the formula with 5 passengers, I sum the 5 revenues and then I divide with 5 passengers if there are more passengers we must sum all of them, and divided all of them, for example:
=(A4+B4+C4+D4+E4+F4)/6
Answer:
Explanation:
Assuming the spoofed 1.2.3.4, it will be sent out ARP to a router that is alive and get it MAC. Then the spoofed packet will be able to be sent out. If A spoofed 10.0.2.30, because it is a local address, it will send an ARP to the machine for been able to get the MAC. But, the IP address 10.0.2.30 is not original making it to be fake, so it will not replay to A, for this reason the spoofed packet cannot be sent out.
