If a woman making $31,000 a year receives a cost-of-living increase of 2.4%, what will her new salary be?

The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c

Slav-nsk [51]

$\text{Answer} : \text{The expected value of a t-shirt is \$31.}$

Explanation:

Since we have given that

The prices of three t-shirts styles i.e $24, $30, $36 with their probability is given by

$\frac{1}{6}, \frac{1}{2},\frac{1}{3}$

As we know that,

$E(X)= \sum_{1}^{3}x_iP(x_i)$

$\text{where} x_i \text{ is the prices of t- shirts styles}$

Now,

$x_1= \$24 , x_2=\$30 , x_3=$36$

and

$P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}$

So,

$E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31$

So, the expected value of a t-shirt = $31.

4 0

2 years ago

David proved the Law of Cosines with reference to ∆ABC using a different method. Arrange the steps of his proof in the correct s

AURORKA [14]

Answer: We can arrange the steps with help of below explanation.

Step-by-step explanation:

Here ABC is a triangle,

Draw a perpendicular from BD to side AC ( construction)

where $D\in AC$

In the right triangle BCD, from the definition of cosine:

cos C =CD/ BC

CD= a cos C

Subtracting this from the side b, we see that

DA= b-acos C

In the triangle BCD, from the definition of sine:

sin C =BD / a

BD = a sin C

In the triangle ADB, applying the Pythagorean Theorem

$c^2 =BD^2 +DA^2$

Substituting for BD and DA from (2) and (3)

$c^2 =(asinC)^2 +(b-acosC)^2$

⇒ $c^2 =a^2sin ^2C+b^2-2ab cosC+a^2 cos ^2C$ ( On simplification)

⇒ $c^2 =a^2sin ^2C+a^2 cos ^2C+b^2-2abcos C$

⇒ $c^2=a^2(sin^2C+cos^2C) +b^2-2abcosC$

⇒ $c^2 = a^2+b^2-2abcosC$ (because, $sin^2\theta+cos^2\theta =1$ )

3 0

2 years ago

What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio

aalyn [17]

Answer:

StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Step-by-step explanation:

Apparently you want to simplify ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}$

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

(a^b)^c = a^(bc)

__

So the expression simplifies as ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}$

9 0

2 years ago

Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce

pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0

2 years ago

The function f(x) = –10(x)(x – 4) represents the approximate height of a projectile launched from the ground into the air with a

sineoko [7]

The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4

Therefore, the projectile stays in the air for
4 seconds

4 0

2 years ago

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