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Greeley [361]
1 year ago
9

Jimmy and John are trying to put a mixture together of blue jelly beans and red jelly beans for a souvenir.gift. The blue jelly

beans cost $0.28 per ounce and the red jelly beans cost $0.55 per ounce. They would like their.gift bags to cost $2.20 per bag. Use complete sentences to explain why or why not it would be reasonable to say that the mixture could contain 4 ounces of blue jelly beans and 3 ounces of red jelly beans.
Mathematics
1 answer:
larisa86 [58]1 year ago
8 0

It is not reasonable for Jimmy and John to say that the mixture has 4 ounces of blue jelly beans and 3 ounces of red jelly beans because it would cost them $2.77 per bag instead of $2.20 per bag. If they were to put 4 ounces of blue jelly beans and 3 ounces of red jelly beans, they would be going over budget.


please rate and thank : )

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According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most
AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 186, \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 + 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.155

His 95% confidence interval is (0.065, 0.155).

4 0
1 year ago
Management is considering adopting a bonus system to increase production. One suggestion is to pay a bonus on the highest 5 perc
Olegator [25]

Answer:

The bonus will be paid on at least 4099 units.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.

In this problem, we have that:

The highest 5 percent is the 95th percentile.

Past records indicate that, on the average, 4,000 units of a small assembly are produced during a week. The distribution of the weekly production is approximately normally distributed with a standard deviation of 60 units. This means that \mu = 4000, \sigma = 60.

If the bonus is paid on the upper 5 percent of production, the bonus will be paid on how many units or more?

The least units that the bonus will be paid is X when Z has a pvalue of 0.95.

Z has a pvalue of 0.95 between 1.64 and 1.65. So we use Z = 1.645

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 4000}{60}

X - 4000 = 60*1.645

X = 4098.7

The number of units is discrete, this means that the bonus will be paid on at least 4099 units.

5 0
2 years ago
James works as a waiter. He served meals with bills of $23.59, $40.65, $30.50, and $15.68. If his total for tips was $17.67, wha
mr_godi [17]
<span><span>1.       </span>James works as a waiter.
He served food with the following price
=> 23.59 dollars
=> 40.65 dollars
=> 30.50 dollars
=> 15.68 dollars
Let’s add this altogether:
=> 23.59 + 40.65 + 30.50 + 15.68
=> 110.42 the total of the ordered food.
Now, James received a tip of 17.67 dollars. Find the interest rate of his tip.
=> 110.42 * .50 = 55.21, thus the interest rate of tip is less than 50%
=> You can do trial and error to get the correct rate,
=> 110.42 * .16 = 17.67, thus he received 16% tip</span>



3 0
2 years ago
Read 2 more answers
EASY MATH PLEASE HELP!! : )
Mademuasel [1]

120

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8 0
1 year ago
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Gekata [30.6K]

Answer:

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Step-by-step explanation:

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2 years ago
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