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2 years ago

Which best explains whether a triangle with side lengths 5 cm, 13 cm, and 12 cm, is a right triangle?

2 answers:

7 0

The Pythagorean Proposition can help you explain this:
${a}^{2} = {b}^{2} + {c}^{2} \\ {13}^{2} = {5}^{2} + {12}^{2} \\ 169 = 25 + 144$

Furkat [3]2 years ago

3 0

Answer:

Let first side= 5 cm

second side= 12 cm

third side = 13 cm

To prove this triangle to be right angle triangle, we need to prove Pythagoras Theorem

$5^{2}$ =25

$12^{2}$ =144

$13^{2}$ =169

169= 25+144

169=169

According to Pythagoras theorem ,

$p^{2}$ + $b^{2}$ = $h^{2}$

since, it follows Pythagoras theorem,

Hence, it is a Right angle Triangle

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If two different people are randomly selected from the 884 subjects, find the probability that they are both women. Round to fou

galina1969 [7]

The answer is 0.3274

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2 years ago

Patty is building a rope ladder tree house she needs two 4 foot pieces of rope for the sides of the ladder she needs 6 pieces of

steposvetlana [31]

Answer:

15.5 feet

Step-by-step explanation:

Given:

Patty is building a rope ladder tree house she needs two 4 foot pieces of rope for the sides of the ladder.

She needs 6 pieces of rope each 15 inches long for the steps.

Question asked:

How many feet of rope does patty need to make the ladder ?

Solution:

She needs for the sides of the ladder = Two 4 foot pieces of rope

= 2 $\times$ 4 feet = 8 feet

She needs for the steps of the ladder = 6 pieces of 15 inches long rope

= 6 $\times$ 15 inches = 90 inches

Convert 90 inches into feet:-

12 inches = 1 feet

1 inches = $\frac{1}{12} \ feet$

90 inches = $\frac{1}{12} \times90=\frac{90}{12} =7.5\ feet$

Patty needs total rope = 8 feet + 7.5 feet

= 15.5 feet

Thus, Patty needs 15.5 feet of rope to make the ladder.

6 0

2 years ago

An adult meerkat weighed 0.776 kilograms . this is 7.47 hectograms more than the weight of a baby meerkat . how much dose a baby

Firlakuza [10]

Let x = weight of adult meerkat, y=weight of baby meerkat, Find y.
x=0.776 kg
y+7.47hectogram=x=0.776
Since 1 hectogram = 0.1 kg,
Therefore the weight of baby meerkat is, y= 0.029 kg

7 0

2 years ago

Read 2 more answers

Transversal t cuts parallel lines a and b as shown in the diagram. Which equation is necessarily true?. a) m<1=m<2. b)m&lt

e-lub [12.9K]

M<1≠m<2
m<4≠m<6
m<3 + m<5 = 180° ≠ 90°
m<7≠m<8
Answer:
none of them.

7 0

2 years ago

Read 2 more answers

Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi

s2008m [1.1K]

Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

7 0

2 years ago