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iragen [17]
2 years ago
6

A gardener wants to run a border around the outside of her garden. She plots it on a grid to plan how much she will need. The ga

rden is in the shape of a rectangle with vertices at (3, 9) (5, 9) (3, 3) (5, 3). Find the total length of border needed. 8ft 12ft 16ft 24ft

Mathematics
1 answer:
liberstina [14]2 years ago
8 0
1. To solve this exercise you must plot the vertices of the rectangle: (3,9);(5,9); (3,3); (5,3). The graph is shown in the figure attached.
<span>
 2. As you can see in the graph, the rectangle has 6 feet long  (L=6 feet) and 2 feet wide (W=2 feet).

 3. Then, the perimeter of the rectangle is:

 P=2L+2W

 4. When you substitute the values of "L" and "W" into </span>P=2L+2W<span>, you obtain:

 P=2(6 feet)+2(2 feet)
 P=12 feet+4 feet
 P=16 feet

 Therefore, the total length of border needed is 16 feet.</span>

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Sam has some red and yellow cubes. She has 20 cubes in total. She has 8 more yellow cubes than red ones. How many red cubes does
Radda [10]

Answer:

12

Step-by-step explanation:

because if she has 8 more red cubes that yellow than that would mean it would become 12

6 0
1 year ago
Read 2 more answers
Given: PRST square
Zigmanuir [339]

Answer:

7a²/16

Step-by-step explanation:

Area of the triangle PTS

½ × a × a

a²/2

Length of PS:

sqrt(a² + a²)

asqrt(2)

Length of MS:

¼asqrt(2)

Triangles MCS and TPS are similar

With sides in the ratio:

¼asqrt(2) : a

sqrt(2)/4 : 1

Area of triangle SMC:

A/(a²/2) = [(sqrt(2)/4)]²

2A/a² = 1/8

A = a²/16

Area of PTMC

= a²/2 - a²/16

= 7a²/16

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
Under what circumstances will the chi-square test for goodness of fit produce a large value for chi-square? Question options: a.
Whitepunk [10]

Answer:

a.when the sample proportions are much different than the hypothesized population proportions

Step-by-step explanation:

A chi-square test for goodness of fit is used to check the sample data were distributed according to claim or not.

If the chi-square test produces a large value of chi-square statistic then there is not a good fit between sample data and the null hypothesis. So, the sample proportions are much different than the hypothesized population proportions. Hence,Option (a) is correct.

If the goodness of fit produces a large value for chi-square then the sample means must not be close to the population mean. So, option (b) is incorrect.

4 0
2 years ago
On an algebra test, the highest grade was 42 points higher than the lowest grade. The sum of the two grades was 138. Find the lo
miv72 [106K]


you could use this equation to help you solve it;

x + (x + 42) = 138

the first step is to combine like terms;

2x = 138 -42

2x = 96

X = 96/2

X = 48

we already solved for x now substitute it in the equation I gave you.

48 + (48 + 42) = 138

48 + 90 = 138

hope it helped...if you have any concerns just let me know:) 

3 0
2 years ago
In △XYZ, m∠Z = 34, x = 61 cm, and z = 42 cm. Find m∠X. Round your answer to the nearest tenth of a degree.
Elza [17]
M∠X = 54.3°.

Using the Law of Sines, we have:
\frac{\sin{Z}}{z}=\frac{\sin{X}}{x}&#10;\\&#10;\\\frac{\sin{34}}{42}=\frac{\sin{X}}{61}

Cross multiplying gives us
61(sin 34) = 42(sin X)

Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X

Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
54.3 = X
8 0
2 years ago
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