(m + n + 3)(m + n + 4) First distribute the m in the first set of parentheses to the second set of parentheses. Do the same process with the n and the 3. m^2 + mn + 4m + mn + n^2 + 4n + 3m +3n + 12 Combine Like terms. Final Answer: m^2 + n^2 + 2mn + 7m + 7n + 12
Only 3 of the nickels are neither dimes nor Canadian. The other 8 of 11 coins are dimes or Canadian. The probability of choosing one of them at random is 8/11.