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9966 [12]
1 year ago
11

On a coordinate grid, point A is at (−3.0, −5.4) and point B is at (−3.0, 5.4). Point B is a reflection of point A across the __

_–axis. Input either a lowercase x or y.
Mathematics
1 answer:
Eddi Din [679]1 year ago
3 0
Given:
Point A (-3.0,-5.4)
Point B (-3.0,5.4)

reflection across y-axis ⇒ (a,b) reflected (-a,b)
reflection across x-axis ⇒ (a,b) reflected (a,-b)
reflection across the origin ⇒ (a,b) reflected (-a,-b)
reflection on y = x ⇒ (a,b) reflected (b,a)

Point B is a reflection of Point A across the x-axis.
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If g(x) = 2x + 2 and h(x) = 4x2 + 8x + 8, find a function f such that f ∘ g = h. (Think about what operations you would have to
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Answer:

Step-by-step explanation:

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1 year ago
When a certain basketball player takes his first shot in a game he succeeds with probability 1/2. If he misses his first shot, h
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Answer:

we are given

basketball player Chauncey Billups of the Detroit Pistons makes free throw shots 88% of the time

so, probability of making shot is

=88%

so, p=0.88

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Step-by-step explanation:

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2 years ago
Mr. Velasquez built a playground. It has one section with a slide and another section with a swing set. A pathway connects the t
posledela

Answer:

A_1 = 24m^2 -- Swing set

A_2 = 16m^2 -- Slide

A_3 = 5m^2 --- Pathway

Step-by-step explanation:

Missing part of the question:

Fill in the table above to show the area of each section (see attachment for table)

The area of each section is calculated as:

Area = Length * Width

For the Swing set

A_1 = 8m * 3m

A_1 = 24m^2

For the Slide

A_2 = 8m * 2m

A_2 = 16m^2

For the Pathway

A_3 = 5m * 1m

A_3 = 5m^2

The total area is:

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Area = 24m^2 + 16m^2 + 5m^2

Area = 45m^2

4 0
1 year ago
I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit
makkiz [27]

Answer:

Possible answer: \displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6.

Step-by-step explanation:

Rewrite the bounds of c as fractions:

The simplest fraction for 1.5 is \displaystyle \frac{3}{2}. Write the upper bound 2 as a fraction with the same denominator:

\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}.

Hence the range for c would be:

\displaystyle \frac{3}{2} < c < \frac{4}{2}.

If the denominator of c is also 2, then the range for its numerator (call it p) would be 3 < p < 4. Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than 2.

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}.

\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}.

At this point, the difference between the numerators is now 2. That allows a number (7 in this case) to fit between the bounds. However, \displaystyle \frac{1}{c} = \frac{4}{7} can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}.

\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}.

\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}.

\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}.

\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}.

\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}.

It is important to note that some expressions for c can be simplified. For example, \displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5} because of the common factor 2.

Apparently \displaystyle c = \frac{16}{10} = \frac{8}{5} works. c = 1.6 while \displaystyle \frac{1}{c} = \frac{5}{8} = 0.625.

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2 years ago
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Reptile [31]

Answer:

1

Step-by-step explanation:

He only has 1 wetsuit and 1 surfboard.

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