ALGEBRA 1 PLEASE HELP

1 answer:

8 0

Subtract the equations straight down. So we'll subtract the x terms together
5x - 5x = 0x = 0
meaning the x terms effectively go away after subtraction

Then we do the y terms together in the same exact order
y-3y = -2y

Then finally the right hand side values
6 - (-5) = 6+5 = 11

All of that work done indicates we have 0x-2y = 11 which is the same as -2y = 11. Divide both sides by -2 and we end up with y = -11/2

This answer isn't listed so I'm thinking there's a typo your teacher made somewhere.

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Sam works as a baggage carrier at an airport facility. He owes a certain amount of money, in dollars, to his friend Daniel. The

Ivenika [448]

Y = 12x - 40

the x variable represents the number of hours Sam works at the airport
the y value represents the amount in dollars that Sam has after paying Daniel
the 12 is the amount in dollars that Sam earns per hr
the 40 is the amount in dollars Sam owes Daniel

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2 years ago

Daisy gave 1/2 of her lanzones to Nuel. Nuel gave 1/3 of the lanzones he received to Ronnie and Ronnie gave 1/4 of what he recei

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Assuming all of them had the same amount at the start

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G identify the solution of the recurrence relation an = 6an − 1 – 8an − 2 for n ≥ 2 together with the initial conditions a0 = 4,

maksim [4K]

Via the generating function method, let

$G(x)=\displaystyle\sum_{n\ge0}a_nx^n$

Then take the recurrence,

$a_n=6a_{n-1}-8a_{n-2}$

multiply everything by $x^n$ and sum over all $n\ge2$ :

$\displaystyle\sum_{n\ge2}a_nx^n=6\sum_{n\ge2}a_{n-1}x^n-8\sum_{n\ge2}a_{n-2}x^n$

Re-index the sums or add/remove terms as needed in order to be able to express them in terms of $G(x)$ :

$\displaystyle\sum_{n\ge2}a_nx^n=\sum_{n\ge0}a_nx^n-(a_0-a_1x)=G(x)-4-10x$

$\displaystyle\sum_{n\ge2}a_{n-1}x^n=\sum_{n\ge1}a_nx^{n+1}=x\sum_{n\ge1}a_nx^n=x\left(G(x)-a_0\right)=x(G(x)-4)$

$\displaystyle\sum_{n\ge2}a_{n-2}x^n=\sum_{n\ge0}a_nx^{n+2}=x^2\sum_{n\ge0}a_nx^n=x^2G(x)$

So the recurrence relation is transformed to

$G(x)-4-10x=6x(G(x)-4)-8x^2G(x)$
$(1-6x+8x^2)G(x)=4-14x$
$G(x)=\dfrac{4-14x}{1-6x+8x^2}=\dfrac{4-14x}{(1-4x)(1-2x)}=\dfrac1{1-4x}+\dfrac3{1-2x}$

For appropriate values of $x$ , we can express the RHS in terms of geometric power series:

$G(x)=\displaystyle\sum_{n\ge0}(4x)^n+3\sum_{n\ge0}(2x)^n=\sum_{n\ge0}\bigg(4^n+3\cdot2^n\bigg)x^n$

which tells us that

$a_n=4^n+3\cdot2^n$

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2 years ago

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

galina1969 [7]

A). because the roots are shown. The roots of this quadratic function would be x=2, and x=-2

8 0

2 years ago

Read 2 more answers

You and your friend are making 30 liters of sodium water. You have liters of 10% sodium and your friend has liters of 22% sodium

iren [92.7K]

X liters of 10% + (30 - x) liters of 22% = 30 liters of 15%

Plugging in the numbers 
x(10) + (30 - x)22 = 30(15) 

Distribute 
10x + 660 - 22x = 450 

Combine like terms 
-12x = -210 

Divide both sides by -12 
x = 17.5 
30 - x = 12.5 

17.5 liters of 10% + 12.5 liters of 22% = 30 liters of 15%

THE TRICK IS TO JUST USE ONLY ONE VARIABLE

4 0

2 years ago