Incomple question. However, here's the remaining part of the question:
14
2009
Meadow Fritillary= 5
Variegated Fritillary= 7
Zebra Swallowtail= 33
Eastern-Tailed Blue= 242
Louden County Butterfly Count
2010
Meadow Fritillary 34
Variegated Fritillary 95
Zebra Swallowtail 21
Eastern-Tailed Blue 168
2011
Meadow Fritillary
Variegated Fritillary
Zebra Swallowtail
Eastern-Tailed Blue
10
170
<u>Options</u>:
A) All butterfly populations are steadily decreasing.
B)All butterfly populations were larger than usual in 2010.
C)The Eastern-Tailed Blue butterfly is more common than the others.
D)The Meadow Fritillary is equally common as the Variegated Fritillary
Answer:
<u>C</u>
Step-by-step explanation:
Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.
Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.
Answer:
D,B,C,A
Step-by-step explanation:
Look at the picture
:)
Comparing the functions, from the tables, it is found that (f - g)(x) is positive in the interval (–∞, 9)
.
----------------------
- For the subtraction function, we simply subtract both functions, thus:
- It is positive if f is greater than g, that is: f(x) > g(x).
- It is a linear function, so one function is greater before the equality, one after.
- They are equal at x = 9.
- If x < 9, f(x) > g(x), and thus, (f - g)(x) is positive, which means that the desired interval is:
(–∞, 9)
A similar problem is given at brainly.com/question/24610273
Answer: The probability that a gene is of type A is 0.29.
Step-by-step explanation:
Let A be the event of type A.
Let B be the event of type B.
Let D be the event of dominant.
So, P(B and D) = 0.22
P(D|B)=0.31
So, Using the conditional probability, we get that
So, the probability that a gene is of type A is given by
Hence, the probability that a gene is of type A is 0.29.
Answer:
g(x)=(x+7)^2-3
Step-by-step explanation:
Given:
f(x)= x^2
Now we have to translate f(x) 7 units to the left and 3 units down to form the function g(x).
As per the rules of translation
when any parent function, in given case f(x)=x^2, is translated to 'a' units to the left then 'a' is added to the value of x. thus making f(x+a)
Also when the parent function is translated any 'a' units down then 'a' is subtracted from the value of function. thus making f(x)-a
Translating f(x), 7 units to the left
f(x+7)= (x+7)^2
Translating f(x+7), 3 units down
f(x+7)-3 = (x+7)^2-3
Hence new function g(x)=(x+7)^2-3!
