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Leto [7]
2 years ago
13

The following comparative stem-and-leaf plot represents the ages (in years) of the members of two professional basketball teams.

Which of the following statements is correct?
A. The youngest player is on Team A, and the oldest player is on Team B.
B. The youngest player is on Team A, and the oldest player is on Team A.
C. The youngest player is on Team B, and the oldest player is on Team A.
D. The youngest player is on Team B, and the oldest player is on Team B.
Mathematics
2 answers:
allochka39001 [22]2 years ago
8 0
Team A              Team B
        8 9 | 1 | 9
  0 0 5 9 | 2 | 2 8 8 9
  1 2 4 4 | 3 | 0 0 4 5 8 9
        0 1 | 4 | 0

Ages of Team A: 18, 19, 20, 20, 25, 29, 31, 32, 34, 34, 40, 41
Ages of Team B: 19, 22, 28, 28, 29, 30, 30, 34, 35, 38, 39, 40

The youngest player is 18 = Team A
The oldest player is 41 = Team A

<span>B. The youngest player is on Team A, and the oldest player is on Team A.</span>
Irina18 [472]2 years ago
8 0

Answer:

D.the youngest player is on team B and the oldest player is on team A

Step-by-step explanation:

apexs

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2 years ago
a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r
galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

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2 years ago
A scuba diver is 33 feet below sea level, while a hiker is 64 feet above sea level directly overhead on the cliffs overlooking t
tino4ka555 [31]

They were 97 feet apart

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2 years ago
Read 2 more answers
A population consists of the following five values: 1, 3, 4, 4, and 6. List all samples of size 2 from left to right without rep
aniked [119]

Answer:

The sample of sizes 2 and their mean are given below.

Step-by-step explanation:

The population consist of  5 values, S = {1, 3, 4, 4, 6}.

The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

{5\choose 2}=\frac{5!}{2!(5-2)!} =10

Th formula to compute the mean is:

\bar x=\frac{1}{n}\sum x_{i}

List the 10 samples and their mean as follows:

<u>Sample</u>                       <u>Mean</u>

(1, 3)                    \bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 4)                    \bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5

(1, 6)                    \bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 4)                   \bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5

(3, 6)                   \bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5

(4, 4)                   \bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

(4, 6)                   \bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0

8 0
2 years ago
A room with a length of 270 cm and width 150 cm is to be covered with square tiles .What is the largest size of tiles to be used
Damm [24]

Find the greatest common factor of both numbers:

Factors for 150:

150: 1, 2, 5 , 6, 10, 15, 25, 30, 50, 75, 150

Factors for 270:

1, 2, 3, 5, 6 , 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270

The largest number they both have in common is 30, so the largest tile could be 30 cm^2.

5 0
2 years ago
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