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8_murik_8 [283]
2 years ago
14

)A mule deer can run one over four of a mile in 25 seconds. At this rate, which expression can be used to determine how fast a m

ule deer runs in miles per hour?
Mathematics
2 answers:
makvit [3.9K]2 years ago
6 0
Well, if you take x to be 25 seconds, there are 2.4x in 1min. So, that multiplied by 60, would be 144x. Therefore, 1/4 multiplied by 144x should be the answer.
Nana76 [90]2 years ago
4 0

The way we work this out is by working out the amount of lots of 25 seconds in an hour, and then multiply it by that 1/4 of an hour. 1 hour has 60 minutes, and each minute has 60 seconds, so 1 x 60 x 60 = 3600 = the number of seconds in an hour.

3600/25 = 144. Therefore there are 144 lots of 25 seconds in an hour. If the deer runs 1/4 a mile in 25 seconds, then we just have to do 144 x 1/4 and it will give us the answer.

144 x 1/4 = 36. Therefore the deer can run 36 miles per hour.

If you want to express this all in one equation, we can write it as:

((60 x 60)/25) x 1/4 = 36

Hope this helped :))

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23^0 is equal to _____. 0 1 1/23 23
Aliun [14]

Answer:

1

Step-by-step explanation:

Anything to the power is 0 is equal to 1.

5 0
1 year ago
Read 2 more answers
Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9. Write the division problem
Sveta_85 [38]

Answer:

The required division problem he must solve is:

\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}

Step-by-step explanation:

Consider the provided information.

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9.

As we know that the quotient of the number is a negative number.

Therefore, the sign of both numbers must be different,

Thus we can concluded he must select \frac{2}{3} as one of the card, so that product is a negative number.

Let the selected card be x.

\frac{2}{3} \div x =\frac{-16}{9}\\\\x=\frac{2}{3}\div\frac{-16}{9}\\\\x=\frac{2}{3}\times\frac{-9}{16}\\\\x=\frac{-3}{8}

Hence, the two cards should be \frac{2}{3} and \frac{-3}{8}

The required division problem he must solve is:

\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}

3 0
2 years ago
Fertiliser is sold in 100kg bags labelled with the amount of nitrogen (N), phosphoric acid (P2O5), and potash (K2O) present. The
anzhelika [568]

Answer:

We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

Step-by-step explanation:

Let's first list the percentage compositions of each fertilizer type:

<u>Vigoro Ultra Turf:</u>

Nitrogen (N) = 29 kg

Phosphoric Acid (P2O5) = 3 kg

Potash (K2O) = 4 kg

<u>Parkers Premium</u>

Nitrogen (N) = 18 kg

Phosphoric Acid (P2O5) = 25 kg

Potash (K2O) = 6 kg

We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:

x = Vigoro Ultra turf (one bag)

y = Parkers Premium (one bag)

29x + 18y = 217   -Equation 1

3x + 25y = 115     -Equation 2

4x + 6y = 44        -Equation 3

Solving for x and y, we get:

x = 5

y = 4

This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.

6 0
2 years ago
The cafe where you work just ran out of coffee, and you are at the store to buy 112 pounds of coffee. You have put a can with 34
ycow [4]

Answer:

78

Step-by-step explanation:

The total you are buying is 112 pounds.  The can you have picked up is 34 pounds; this leaves

112-34 = 78 pounds remaining.

7 0
2 years ago
Read 2 more answers
What additional information could you use to show that ΔSTU ≅ ΔVTU using SAS? Check all that apply.
GalinKa [24]

Options

A. UV = 14 ft and m∠TUV = 45°

B. TU = 26 ft

C. m∠STU = 37° and m∠VTU = 37°

D. ST = 20 ft, UV = 14 ft, and m∠UST = 98°

E. m∠UST = 98° and m ∠TUV = 45°

Answer:

A. UV = 14 ft and m∠TUV = 45°

D. ST = 20 ft, UV = 14 ft, and m∠UST = 98°

Step-by-step explanation:

Given

See attachment for triangle

Required

What proves that: ΔSTU ≅ ΔVTU using SAS

To prove their similarity, we must check the corresponding sides and angles of both triangles

First:

\angle UST must equal \angle UVT

So:

\angle UST = \angle UVT = 98

Next:

UV must equal US.

So:

UV = US = 14

Also:

ST must equal VT

So:

ST = VT = 20

Lastly

\angle TUV must equal \angle TUS

So:

\angle TUV = \angle TUS = 45

Hence: Options A and D are correct

4 0
2 years ago
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