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velikii [3]
2 years ago
14

A karate center has 120 students. The director wants to set a goal to motivate her instructors to increase student enrollment. U

nder plan A, the goal is to increase the number of students by 12% each year. Under plan B, the goal is to increase the number of students by 20 each year.
A) Compare the plans.
B) Which plan should the director choose to double the enrollment in the shortest amount of time? Explain.
C) Which plan should she use to triple the enrollment in the shortest amount of time? Explain.
Mathematics
1 answer:
iVinArrow [24]2 years ago
3 0
A) Plan A requires for a percentage increase of a number of students. This means that year after year the number of new students will increase. Plan B requires for a constant number of new students each year. This means that year after year the percentage increase would get smaller.

B) To solve this problem we will use formula for a growth of population:
final = initial * (1+percentage)^{t}
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years

We can insert numbers and solve for t:
240= 120* (1+0.12)^{t}  \\ 2=1.12^{t}   \\ log2=log(1.12^{t} ) \\ log2=t*log1.12 \\ t= \frac{log2}{log1.12}  \\ t=6.12years

For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years

Plan B is better to double the <span>enrollment.


C)We use same steps as in B) to solve this.
</span>

360= 120* (1+0.12)^{t} \\ 3=1.12^{t} \\ log3=log(1.12^{t} ) \\ log3=t*log1.12 \\ t= \frac{log3}{log1.12} \\ t=9.69years

For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years

Plan A is better to triple the enrollment.
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Remember
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The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
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Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

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viktelen [127]

Answer:

Marcus is picking songs to play during a slideshow. The songs are each 3\dfrac123  

2

1

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3, start fraction, 1, divided by, 2, end fraction minutes long. The slideshow is 31\dfrac1231  

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31, start fraction, 1, divided by, 2, end fraction minutes long.

Step-by-step explanation:

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