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muminat
2 years ago
6

The figure shows a negatively charged sphere and a balloon that has been rubbed with dry human hair. If the two are brought clos

e to each other but do not touch each other, you can predict that the objects will
Chemistry
2 answers:
Westkost [7]2 years ago
4 0
TBH I feel as if you want to say they'll attract due to the static electricity but, I can't be too sure. If I do say so myself the balloon will pop due to the static electricity.
Ad libitum [116K]2 years ago
3 0
The correct answer is that they will repel. Because the balloon turns negatively charged after it gets rubbed on human hair, and the human hair is negatively charged also. That's why the hair flares up after the balloon gets rubbed and then closer to the hair again because opposite charges attract while the same repel.

I'm 100% positive that this is correct, I took the test and this is the most reasonable explanation.    Hope this Heeelpps! ^u^

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A high school class is discussing whether a particular discovery in chemistry has had a positive impact on society. Which questi
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The standard free energy ( Δ G ∘ ′ ) (ΔG∘′) of the creatine kinase reaction is − 12.6 kJ ⋅ mol − 1 . −12.6 kJ⋅mol−1. The Δ G ΔG
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Answer:

The concentration of [ADP] = 21.896*10^-6 μM

Explanation:

Given Data:

creatine + ATP -----------> ADP + creatine phosphate    

ΔG∘   = -12.6 KJ/mole  = -12600 J/mole

ΔG = -0.1 KJ/mole  =  -100 J/mole

[Creatine phosphate]  = 25 mM = 25*10^-3 M

[Creatine] = 17 mM    = 17*10^-3 M

[ATP]   =5mM = 5*10^-3M

Calculating the concentration of [ADP] using the formula;

ΔG = ΔG∘ + RTlnQc

Substituting, we have

-12600   = -100 + 8.314*298lnQc

-12600+100 = 8.314*298lnQc

-12500   = 2477.57lnQc

lnQc = -12500/2477.57

lnQc = -5.045

Qc = e^ -5.045

Qc   = 6.44*10^-3

But,

Qc    = [Creatine phosphate]*[ADP]/[creatine]*[ATP]

6.44*10^-3   = 25*10^-3*[ADP]/ (17*10^-3* 5*10^-3)

6.44*10^-3 = 25*10^-3[ADP]/8.5*10^-5

6.44*10^-3 * 8.5*10^-5 = 25*10^-3[ADP]

5.474*10^-7 = 25*10^-3[ADP]

[ADP] = 5.474*10^-7 /25*10^-3

          = 2.1896 *10^-5 M

          = 21.896*10^-6 μM

Therefore, the concentration of [ADP] = 21.896*10^-6 μM

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