Answer: First option.
Step-by-step explanation:
The complete exercise is attached.
In order to solve this exercise, it is necessary to remember the following property:
The Multiplication property of Equality states that:
In this case, the equation that Jada had is the folllowing:
Jada needed to solve for the variable "x" in order to find its value.
The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:
As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by 
<em> </em>and the right side by 
.
Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.
Card P's balance increased by $3.43 more than Card Q's balance. The accumulated total on Card P over the 4 years is $1080.70 and the accumulated total of Card Q is $1,206.28. Based on the principal outlay however, Card P would have netted a higher interest over Card Q when the principal is subtracted from the accumulated value. (For eg. Card P accumulated value $1080.70 less Principal $726.19 equals $354.51).The interests over the 4 years period would be $354.51 and $351.08 respectively, hence Card P having an increase in balance of $3.43 over Card Q.
S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3
S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24
For the sake of simplicity, let us say that the bottle contains x liters of water.
The pail originally contained x+3.68 L of water
After pouring out 1.2L, the pail contains x+(3.68-1.2)L or x+2.48 L
<span>
(a) How much more water did the pail contain than the bottle in the end?
Since the bottle contains x L of water, the pail (containing x+2.48 L of water) contains (x+2.48) - x more liters of water than the bottle or "the pail contained 2.48 L of water more than the bottle"
</span><span>(b) How much water did the bottle contain?
</span>We are told that after pouring the 1.2L of water out, the pail contained 3 times as much water as the pail. Therefore, 3x = x+2.48. Subtracting x from both sides gives us 2x = 2.48. Dividing both sides by 2 gives us x = 1.24L
Answer:
The solution to f(x) = t(x) is x = 2010
Option 3 is true.
Step-by-step explanation:
The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.
Year (x) First Year f(x) Second Year s(x) Third Year t(x)
2009 785 756 756
2010 740 785 740
2011 690 710 781
2012 732 732 710
2013 781 755 800
Now we will check each option.
Option 1: The solution to f(x) = s(x) is x = 2,009
In year 2009, f(x)=s(x)
But 785≠756
Thus, False
Option 2: The solution to f(x) = s(x) is x = 785
x represents year, but 785 it no year
Thus, False
Option 3: The solution to f(x) = t(x) is x = 2010
In year 2010, f(x)=t(x)=740
But 740=740
Thus, True
Option 4: The solution to f(x) = t(x) is x =740
x represents year, but 740 it no year
Thus, False
