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Lady_Fox [76]
2 years ago
12

Evaluate the upper and lower sums for f(x) = 2 + sin(x), 0 ≤ x ≤ π, with n = 2, 4, and 8. Illustrate with diagrams like the figu

re shown below. (Round your answers to two decimal places.)
Mathematics
1 answer:
larisa [96]2 years ago
8 0

f(x)=x+sin(x)\\ a=0\\ b=\pi \\ x_i=a+idelta(x)\\ Upper sum for n=2:\\ \\ delta(x)=\frac{b-a}{n} =\frac{\pi-0}{2} =\frac{\pi}{2}

x_0=0, x_1=\frac{\pi}{2} ,x_1=\pi  \\

Length of the subintervals: [0,\frac{\pi}{2}], [\frac{\pi}{2}, \pi}]

Using Upper Riemann sum,

\int\limits^0_\pi{x+sin(x)\, dx  =∑Max{f(x_i) delta(x)

=[max{(f(x_1))+max(f(x_2))]delta(x)\\ =(3+3)\frac{\pi}{2} \\=9.42

Lower sum for n=2:

The minimum value for the function on [0,\frac{\pi}{2}], [\frac{\pi}{2}, \pi] is 2.

\int\limits^0_\pi {x+\sin x} \, dx  =\sum_{n=0}^{n=2} min {f(x_i)} delta (x)\\

= (2+2)\frac{\pi}{2}\\ =6.28

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Area of a trapezoid:
A = 1/2 * ( b 1 + b 2) *h
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3.2.PS-33 Liam has 63 CDs​, Alex has 49 CDs​, and Michael has 77 CDs. Use the GCF and the Distributive Property to find the tota
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Answer:

The total number of CDs Liam​, Alex​, and Michael have is <u>189</u>.

Step-by-step explanation:

Given:

Liam has 63 CDs​, Alex has 49 CDs​, and Michael has 77 CDs.

Now, to find the total number of CDs using the GCF and the Distributive Property.

So, the CDs are :

Liam = 63.

Alex = 49.

Michael = 77.

Now, we factorize all the Number of CDs of Liam, Alex and Michael to get the GCF:

The factors of 63 are: 1, 3, 7, 9, 21, 63

The factors of 49 are: 1, 7, 49

The factors of 77 are: 1, 7, 11, 77

Thus, 7 is the GCF.

Now, we use the distributive property to get the total number of CDs Liam​, Alex​, and Michael have:

7(9+7+11)

=63+49+77

=189.

Therefore, the total number of CDs Liam​, Alex​, and Michael have is 189.

8 0
2 years ago
The following data represent weights in kilograms of maize harvest from a random sample of 72 experimental plots on St. Vincent,
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Answer:

See explanation

Step-by-step explanation:

7.8 9.1 9.5 10.0 10.2 10.5 11.1 11.5 11.7 11.8

12.2 12.2 12.5 13.1 13.5 13.7 13.7 <u>14.0 14.4</u> 14.5

14.6 15.2 15.5 16.0 16.0 16.1 16.5 17.2 17.8 18.2

19.0 19.1 19.3 19.8 20.0 20.2 20.3 20.5 20.9 21.1

21.4 21.8 22.0 22.0 22.4 22.5 22.5 22.8 22.8 23.1

23.1 23.2 23.7 <u>23.8 23.8</u> 23.8 23.8 24.0 24.1 24.1

24.5 24.5 24.9 25.1 25.2 25.5 26.1 26.4 26.5 26.7

27.1 29.5

A. The five-number summary is

  • Minimum = 7.8
  • Maximum = 29.5
  • Median =\dfrac{20.2+20.3}{2}=20.25
  • Q_1=\dfrac{14.0+14.4}{2}=14.2
  • Q_3=\dfrac{23.8+23.8}{2}=23.8

B. The interquartile range is

Q_3-Q_1=23.8-14.2=9.6

C. See attached diagram

D. The distribution is not symmetric, the left half shows more data than the right part

7 0
2 years ago
A population consists of 500 elements. We want to draw a simple random sample of 50 elements from this population. On the first
larisa [96]

Answer:

D. 0.002

Step-by-step explanation:

Given;

total number of sample, N = 500 elements

50 elements are to be drawn from this sample.

The probability of the first selection, out of the 50 elements to be drawn will be = 1 / total number of sample

The probability of the first selection = 1 / 500

The probability of the first selection = 0.002

Therefore, on the first selection, the probability of an element being selected is 0.002

The correct option is "D. 0.002"

4 0
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