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patriot [66]
2 years ago
11

Study this table. x y –3 –2 –2 0 0 4 4 12 Which best describes the function represented by the data in the table? linear with a

common ratio of 2 linear with a common first difference of 2 quadratic with a common ratio of 2 quadratic with a common first difference of 2
Mathematics
2 answers:
ss7ja [257]2 years ago
7 0

we can do this by 2 ways

1- by plotting the points on graph and then tracing the points to get shape,

for linear, we will get straight line

for quadratic, we will get parabola

in this case, it is linear as we get a straight line

2- by solving for values of x and y

consider standard linear equation y = mx +c where m is slope and c is constant

by putting given values of x and y we get

y + 2x = 4(answer)

if we consider standard parabola equation

y^2 = 4ax

this equation is not true for given points

Brut [27]2 years ago
7 0

Answer:

linear with a common first difference of 2

Step-by-step explanation:

If this is linear, the common first difference, or slope, will be the same throughout the entire table.

The formula for slope is

m=\frac{y_2-y_1}{x_2-x_1}

For the first set of points, we have:

m=(0--2)/(-2--3) = (0+2)/(-2+3) = 2/1 = 2

For the second set of points, we have:

m = (4-0)/(0--2) = 4/(0+2) = 4/2 = 2

For the third set of points, we have:

m = (12-4)/(4-0) = 8/4 = 2

The rate of change, or slope, is constant; this makes the function a linear function with a common first difference of 2.

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Step-by-step explanation:

The electrical force between two unlike charge is given by :

F=\dfrac{kq_1q_2}{r^2}

k is electrostatic constant

q₁ and q₂ are two charges

r is the distance between charges

It is clear that the electric force is inversely proportional to the square of the distance between them.

The graph F as a function of r for two positive charges is shown in the attached figure. It is a hyperbola.

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What is the coefficient in the expression 5 + 9y?
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yesyes

Step-by-step explanation:

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Which of the following is the radical expression of a to the four ninths power?
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\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\large\huge\boxed{a^\frac{4}{9}=\sqrt[9]{a^4}}

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A parabolic satellite dish reflects signals to the dish’s focal point. An antenna designer analyzed signals transmitted to a sat
ivolga24 [154]

Answer:

c=\frac{16}{39}

Step-by-step explanation:

The probability density function is :

f(x)=c(1-\frac{1}{16}x^{2})

With 0 < x < 3

To be a valid probability density function :

\int\limits^b_a {f(x)} \,dx=1

Where a < x < b

And also

f(x) ≥ 0 for a < x < b

Applying this to the probability density function of the exercise :

\int\limits^3_0 {c(1-\frac{1}{16}x^{2})} \, dx=1

c\int\limits^3_0 {(1-\frac{1}{16}x^{2})} \, dx=1

c(3-\frac{1}{16}\frac{3^{3}}{3})=1

c(\frac{39}{16})=1

c=\frac{16}{39}

We can verify by replacing ''c'' in the original probability density function and integrating :

\int\limits^3_0 {\frac{16}{39}(1-\frac{1}{16}x^{2})} \, dx=

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4 0
3 years ago
The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
Dahasolnce [82]

Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

4 0
2 years ago
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